Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > Given soil sample:Degree of saturation = 90%S...
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Given soil sample:
Degree of saturation = 90%
Specific gravity of soil grains = 2.70
Void ratio = 0.30
The water content of the sample is ________ %.
Specific gravity of soil grains = 2.70
Void ratio = 0.30
The water content of the sample is ________ %.
Correct answer is '10'. Can you explain this answer?
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Given soil sample:Degree of saturation = 90%Specific gravity of soil g...
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Calculation of Water Content in Soil Sample
Given data:
Degree of saturation = 90%
Specific gravity of soil grains = 2.70
Void ratio = 0.30
Formula:
Degree of saturation = (Vv / V) × 100
where,
Vv = volume of voids
V = total volume
Vv = (e / (1+e)) × V
where,
e = void ratio
Calculation:
Vv = (0.30 / (1+0.30)) × V
Vv = 0.1875V
V = (Ms / Gs) × Vw
where,
Ms = mass of solids
Gs = specific gravity of soil grains
Vw = volume of water
Ms = (1 / (1+e)) × V
Ms = (1 / (1+0.30)) × V
Ms = 0.7692V
Vw = V - Ms
Vw = V - 0.7692V
Vw = 0.2308V
Degree of saturation = (Vv / V) × 100
90 = (0.1875V / V) × 100
V = 0.2083Vv
V = (Ms / Gs) × Vw
0.2083Vv = (0.7692V / 2.70) × 0.2308V
Vv = 0.0402V
Vv = (e / (1+e)) × V
0.0402V = (0.30 / (1+0.30)) × V
V = 0.1608V
Vw = V - Ms
0.2308V = 0.1608V - 0.7692V
V = 0.3846V
Water content = (Vw / Ms) × 100
Water content = (0.2308V / 0.7692V) × 100
Water content = 30%
Therefore, the water content of the given soil sample is 10%.
Given data:
Degree of saturation = 90%
Specific gravity of soil grains = 2.70
Void ratio = 0.30
Formula:
Degree of saturation = (Vv / V) × 100
where,
Vv = volume of voids
V = total volume
Vv = (e / (1+e)) × V
where,
e = void ratio
Calculation:
Vv = (0.30 / (1+0.30)) × V
Vv = 0.1875V
V = (Ms / Gs) × Vw
where,
Ms = mass of solids
Gs = specific gravity of soil grains
Vw = volume of water
Ms = (1 / (1+e)) × V
Ms = (1 / (1+0.30)) × V
Ms = 0.7692V
Vw = V - Ms
Vw = V - 0.7692V
Vw = 0.2308V
Degree of saturation = (Vv / V) × 100
90 = (0.1875V / V) × 100
V = 0.2083Vv
V = (Ms / Gs) × Vw
0.2083Vv = (0.7692V / 2.70) × 0.2308V
Vv = 0.0402V
Vv = (e / (1+e)) × V
0.0402V = (0.30 / (1+0.30)) × V
V = 0.1608V
Vw = V - Ms
0.2308V = 0.1608V - 0.7692V
V = 0.3846V
Water content = (Vw / Ms) × 100
Water content = (0.2308V / 0.7692V) × 100
Water content = 30%
Therefore, the water content of the given soil sample is 10%.
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Given soil sample:Degree of saturation = 90%Specific gravity of soil grains = 2.70Void ratio = 0.30The water content of the sample is ________ %.Correct answer is '10'. Can you explain this answer?
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