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The resistance of 0.01N solution of an electrolyte AB at 328K is 100 ohm. The specific conductance of solution is (cell constant = 1cm-1) -
- a)100 ohm
- b)10-2 ohm-1
- c)10-2 ohm-1 cm-1
- d)102 ohm-cm
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The resistance of 0.01N solution of an electrolyte AB at 328K is 100 o...
Specific conductance is defined as the conductance of a material or solution occupying one cm^3 volume.
Moreover, Specific conductance, K is inversely proportional to resistance
Moreover, Specific conductance, K is inversely proportional to resistance
i.e., K = Cell constant /R
= 1 cm^-1 / 100 = 10^-2 ohm^-1cm^-1
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The resistance of 0.01N solution of an electrolyte AB at 328K is 100 o...
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The resistance of 0.01N solution of an electrolyte AB at 328K is 100 o...
Given:
- Resistance of 0.01N solution of electrolyte AB at 328K = 100 ohm
- Cell constant = 1 cm^-1
To find:
Specific conductance of the solution
Formula:
Specific conductance (κ) = Conductivity (σ) × Cell constant (C)
Explanation:
The specific conductance of a solution is a measure of its ability to conduct electricity. It is defined as the conductance of a solution of unit volume (1 cm^3) and unit area of cross-section (1 cm^2).
We are given the resistance of the solution, which can be used to calculate the conductivity using Ohm's Law.
Step 1: Calculation of Conductivity
Using Ohm's Law:
Resistance (R) = ρ × (L/A), where ρ is the resistivity, L is the length of the conductor, and A is the cross-sectional area.
In this case, the resistance (R) is given as 100 ohm, and the length (L) and cross-sectional area (A) are not given. However, since the cell constant (C) is given as 1 cm^-1, we can assume that the length and cross-sectional area are both equal to 1 cm.
So, the resistivity (ρ) can be calculated as:
ρ = R × (A/L) = 100 ohm × (1 cm/1 cm) = 100 ohm × 1 = 100 ohm-cm
The conductivity (σ) is the reciprocal of resistivity:
σ = 1/ρ = 1/100 ohm-cm = 0.01 ohm^-1-cm^-1
Step 2: Calculation of Specific Conductance
Using the formula:
Specific conductance (κ) = Conductivity (σ) × Cell constant (C)
κ = 0.01 ohm^-1-cm^-1 × 1 cm^-1 = 0.01 ohm^-1-cm^-1
Answer:
The specific conductance of the 0.01N solution of electrolyte AB at 328K is 0.01 ohm^-1-cm^-1. Option C is the correct answer.
- Resistance of 0.01N solution of electrolyte AB at 328K = 100 ohm
- Cell constant = 1 cm^-1
To find:
Specific conductance of the solution
Formula:
Specific conductance (κ) = Conductivity (σ) × Cell constant (C)
Explanation:
The specific conductance of a solution is a measure of its ability to conduct electricity. It is defined as the conductance of a solution of unit volume (1 cm^3) and unit area of cross-section (1 cm^2).
We are given the resistance of the solution, which can be used to calculate the conductivity using Ohm's Law.
Step 1: Calculation of Conductivity
Using Ohm's Law:
Resistance (R) = ρ × (L/A), where ρ is the resistivity, L is the length of the conductor, and A is the cross-sectional area.
In this case, the resistance (R) is given as 100 ohm, and the length (L) and cross-sectional area (A) are not given. However, since the cell constant (C) is given as 1 cm^-1, we can assume that the length and cross-sectional area are both equal to 1 cm.
So, the resistivity (ρ) can be calculated as:
ρ = R × (A/L) = 100 ohm × (1 cm/1 cm) = 100 ohm × 1 = 100 ohm-cm
The conductivity (σ) is the reciprocal of resistivity:
σ = 1/ρ = 1/100 ohm-cm = 0.01 ohm^-1-cm^-1
Step 2: Calculation of Specific Conductance
Using the formula:
Specific conductance (κ) = Conductivity (σ) × Cell constant (C)
κ = 0.01 ohm^-1-cm^-1 × 1 cm^-1 = 0.01 ohm^-1-cm^-1
Answer:
The specific conductance of the 0.01N solution of electrolyte AB at 328K is 0.01 ohm^-1-cm^-1. Option C is the correct answer.
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The resistance of 0.01N solution of an electrolyte AB at 328K is 100 ohm. The specific conductance of solution is (cell constant = 1cm-1) -a)100 ohmb)10-2ohm-1c)10-2ohm-1cm-1d)102ohm-cmCorrect answer is option 'C'. Can you explain this answer?
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