The resistance is a solution work specific conductance 1.6x10raised to -2 placed in a cell with parallel electrodes each of area 1.6cm.square is 300 ohms. The distance between the parallel electrodes is.?????

Question

Answer

L/A= R×(specific conductivity)

Answer

Understanding the Problem
To find the distance between the parallel electrodes, we can use the relationship between resistance, specific conductance, area, and distance.
Key Parameters
- Specific Conductance (κ): 1.6 x 10^-2 S/m
- Resistance (R): 300 ohms
- Area (A): 1.6 cm² = 1.6 x 10^-4 m² (conversion from cm² to m²)
Formula to Use
The relationship between resistance (R), specific conductance (κ), area (A), and distance (d) is given by:
R = d / (κ * A)
From this formula, we can rearrange it to find the distance (d):
d = R * (κ * A)
Calculating Distance
1. Convert Area:
- A = 1.6 cm² = 1.6 x 10^-4 m²
2. Substituting Values:
- d = 300 ohms * (1.6 x 10^-2 S/m * 1.6 x 10^-4 m²)
3. Calculating d:
- d = 300 * (1.6 x 10^-2 * 1.6 x 10^-4)
- d = 300 * 2.56 x 10^-6
- d = 7.68 x 10^-4 m = 0.768 mm
Final Result
The distance between the parallel electrodes is approximately 0.768 mm. This calculation shows how resistance, specific conductance, and electrode area interrelate to determine the distance, reflecting the fundamental principles of electrical conductivity in solutions.

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