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 Specific conductance of a 0.1 N KCl solution at 23ºC is 0.012 ohm–1 cm–1. Resistance of cell containing the solution at same temperature was found to be 55 ohm. The cell constant is [2000]
  • a)
    0.918 cm–1
  • b)
    0.66 cm–1
  • c)
    1.142 cm–1
  • d)
    1.12 cm–1
Correct answer is option 'B'. Can you explain this answer?
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Specific conductance of a 0.1 N KCl solution at 23ºC is 0.012 ohm...
Given specific conductance of the solution (k) = 0.012 ohm–1 cm–1 and resistance (R) = 55 ohm. We know that cell constant = Specific conductance × Observed resistance = 0.012 × 55= 0.66cm–1.
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Specific conductance of a 0.1 N KCl solution at 23ºC is 0.012 ohm–1 cm–1. Resistance of cell containing the solution at same temperature was found to be 55 ohm. The cell constant is [2000]a)0.918 cm–1b)0.66 cm–1c)1.142 cm–1d)1.12 cm–1Correct answer is option 'B'. Can you explain this answer?
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Specific conductance of a 0.1 N KCl solution at 23ºC is 0.012 ohm–1 cm–1. Resistance of cell containing the solution at same temperature was found to be 55 ohm. The cell constant is [2000]a)0.918 cm–1b)0.66 cm–1c)1.142 cm–1d)1.12 cm–1Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Specific conductance of a 0.1 N KCl solution at 23ºC is 0.012 ohm–1 cm–1. Resistance of cell containing the solution at same temperature was found to be 55 ohm. The cell constant is [2000]a)0.918 cm–1b)0.66 cm–1c)1.142 cm–1d)1.12 cm–1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Specific conductance of a 0.1 N KCl solution at 23ºC is 0.012 ohm–1 cm–1. Resistance of cell containing the solution at same temperature was found to be 55 ohm. The cell constant is [2000]a)0.918 cm–1b)0.66 cm–1c)1.142 cm–1d)1.12 cm–1Correct answer is option 'B'. Can you explain this answer?.
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