PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, andDelta;rGanddeg;, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by andbeta;. Thus, andbeta;equilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar Kandndash;1 molandndash;1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)andbeta;equilibrium = 0.7d)KC andlt; 1Correct answer is option 'C'. Can you explain this answer?

EduRev

All Courses

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

JEE Exam > JEE Questions > PARAGRAPH 2Thermal decomposition of gaseous X...

Join the Discussion on the App

PARAGRAPH 2

Thermal decomposition of gaseous X₂ to gaseous X at 298 K takes place according to the following equation:

The standard reaction Gibbs energy, Δ_rG°, of this reaction is positive. At the start of the reaction, there is one mole of X₂and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, β_equilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.

(Given R = 0.083 L bar K^–1 mol^–1)

Q. The INCORRECT statement among the following, for this reaction, is

a)
Decrease in the total pressure will result in formation of more moles of gaseous X
b)
At the start of the reaction, dissociation of gaseous X₂ takes place spontaneously
c)
β_equilibrium = 0.7
d)
K_C < 1

Correct answer is option 'C'. Can you explain this answer?

FREE This question is part of

Test: JEE Main 35 Year PYQs- Equilibrium

Attempt Test

Attempt this Test

Verified Answer

PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K t...

(A) Correct statement.
As on decrease in pressure reaction move indirection where no. of gaseous molecules increase.
(B) Correct statement At the start of reaction Q_P < K_P so dissociation of X₂ take place spontaneousely.
(C) Incorrect statement as

View all questions of this test

View all answers Start learning for free

< Previous Question Next Question >

Explore Courses for JEE exam

Similar JEE Doubts

Paragraph 1Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG0, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given: R = 0.083 L bar K-1 mol-1)Q.The INCORRECT statement among the following, for this reaction is

View answer

PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The equilibrium constant Kp for this reaction at 298 K, in terms ofβequilibrium, is

View answer

This section contains TWO paragraphsBased on each paragraph, there will be TWO questionsEach question has FOUR options (

View answer

For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.The K for the reaction is 640 mm at 775 K. The percentage dissociation of N2O4 at equilibrium pressure of 160 mm is

View answer

For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.A sample of mixture of A(g), B(g) and C(g) under equilibrium has a mean molecular weight (observe d) is 80.The equilibrium is Find the degree of dissociation for A(g).

View answer

Top Courses for JEEView all

Physics for JEE Main & Advanced

Mock Tests for JEE Main and Advanced 2025

Chemistry for JEE Main & Advanced

Mathematics (Maths) for JEE Main & Advanced

Chapter-wise Tests for JEE Main & Advanced

Top Courses for JEE

View all

PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer?

Share with a Friend

Answer this doubt

Question Description
PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer?.

Solutions for PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer?, a detailed solution for PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice PARAGRAPH 2Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation:The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.(Given R = 0.083 L bar K–1 mol–1)Q.The INCORRECT statement among the following, for this reaction, isa)Decrease in the total pressure will result in formation of more moles of gaseous Xb)At the start of the reaction, dissociation of gaseous X2 takes place spontaneouslyc)βequilibrium = 0.7d)KC < 1Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.

Explore Courses for JEE exam