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A conductor of length 0.6 m is situated at the right angle to a uniform magnetic field of flux density 4 Wb/sq. m. The conductor is moving with a velocity of 50 m/s. Calculate the emf induced (in V) n the conductor.
  • a)
    100
  • b)
    115
  • c)
    118
  • d)
    120
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A conductor of length 0.6 m is situated at the right angle to a unifor...
Given that, Magnetic flux density (B) = 4 Wb/sq. m.
Length (l) = 0.6 m
Velocity (v) = 50 m/s
Emf induced is, E=Blvsinθ
E=4×0.6×50×sin90=120
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Most Upvoted Answer
A conductor of length 0.6 m is situated at the right angle to a unifor...
Given data:
- Length of the conductor (l) = 0.6 m
- Flux density (B) = 4 Wb/sq. m
- Velocity of the conductor (v) = 50 m/s

To find:
- The induced emf in the conductor

The emf induced in a conductor moving at a right angle to a magnetic field can be calculated using the formula:

emf = B * l * v

where B is the flux density, l is the length of the conductor, and v is the velocity of the conductor.

Calculation:
Substituting the given values into the formula, we have:

emf = 4 Wb/sq. m * 0.6 m * 50 m/s
= 120 V

Therefore, the induced emf in the conductor is 120 V.

Hence, the correct answer is option 'D' - 120.
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A conductor of length 0.6 m is situated at the right angle to a uniform magnetic field of flux density 4 Wb/sq. m. The conductor is moving with a velocity of 50 m/s. Calculate the emf induced (in V) n the conductor.a)100b)115c)118d)120Correct answer is option 'D'. Can you explain this answer?
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