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Determine the self-inductance (in mH) of a 3 m long air-cored solenoid, when the coil has 300 turns and the diameter of the coil 12 cm.
  • a)
    0.41
  • b)
    0.35
  • c)
    0.32
  • d)
    0.24
Correct answer is option 'A'. Can you explain this answer?
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Determine the self-inductance (in mH) of a 3 m long air-cored solenoid...
Inductance of a solenoid is given by,
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Determine the self-inductance (in mH) of a 3 m long air-cored solenoid...
Given data:

Length of the solenoid, l = 3 m

Number of turns, N = 300

Diameter of the solenoid, d = 12 cm = 0.12 m

Formula used:

Self-inductance of a solenoid, L = (μ₀*N²*A)/l

where,

μ₀ = Permeability of free space = 4π × 10⁻⁷ H/m

N = Number of turns

A = Cross-sectional area of the solenoid

l = Length of the solenoid

Calculation:

Radius of the solenoid, r = d/2 = 0.06 m

Cross-sectional area of the solenoid, A = π*r² = 0.01131 m²

Substituting the given values in the formula, we get

L = (4π × 10⁻⁷ * 300² * 0.01131) / 3

L = 0.412 mH (approx)

Therefore, the self-inductance of the solenoid is 0.41 mH (approx).

Hence, option (a) is the correct answer.
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Community Answer
Determine the self-inductance (in mH) of a 3 m long air-cored solenoid...
Inductance of a solenoid is given by,
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Determine the self-inductance (in mH) of a 3 m long air-cored solenoid, when the coil has 300 turns and the diameter of the coil 12 cm.a)0.41b)0.35c)0.32d)0.24Correct answer is option 'A'. Can you explain this answer?
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