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 The differential equation formed by y= acosx + bsinx + 4 where a and b are arbitrary constants is :

  • a)
    (d2y/dx2) + y = 0

  • b)
    (d2y/dx2) – y = 0

  • c)
    (d2y/dx2) + y = 4

  • d)
    (d2y/dx2) – y = 4​

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The differential equation formed byy=acosx+bsinx+ 4 whereaandbare arbi...
y = acosx + bsinx + 4
⟹dy/dx ​= −asinx + bcosx + 4
⟹d2y​/dx= −acosx − bsinx 
⟹d2y​/dx= −y
⟹ d2y​/dx+ y = 0
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Most Upvoted Answer
The differential equation formed byy=acosx+bsinx+ 4 whereaandbare arbi...
Y= -a*cosx - b*sinx
c)(d2y/dx2) y= -a*sinx + b*cosx
d)(d2y/dx2) y= a*sinx + b*cosx

Solution:
We have,
y = a*cosx + b*sinx + 4
Differentiating w.r.t x, we get
dy/dx = -a*sinx + b*cosx
Differentiating again w.r.t x, we get
d^2y/dx^2 = -a*cosx - b*sinx
Hence, the answer is option (c) (d2y/dx2) y= -a*sinx + b*cosx.
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The differential equation formed byy=acosx+bsinx+ 4 whereaandbare arbi...
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The differential equation formed byy=acosx+bsinx+ 4 whereaandbare arbitraryconstants is :a)(d2y/dx2) +y= 0b)(d2y/dx2) –y= 0c)(d2y/dx2) +y= 4d)(d2y/dx2) –y= 4Correct answer is option 'C'. Can you explain this answer?
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The differential equation formed byy=acosx+bsinx+ 4 whereaandbare arbitraryconstants is :a)(d2y/dx2) +y= 0b)(d2y/dx2) –y= 0c)(d2y/dx2) +y= 4d)(d2y/dx2) –y= 4Correct answer is option 'C'. Can you explain this answer? for Engineering Mathematics 2024 is part of Engineering Mathematics preparation. The Question and answers have been prepared according to the Engineering Mathematics exam syllabus. Information about The differential equation formed byy=acosx+bsinx+ 4 whereaandbare arbitraryconstants is :a)(d2y/dx2) +y= 0b)(d2y/dx2) –y= 0c)(d2y/dx2) +y= 4d)(d2y/dx2) –y= 4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Engineering Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The differential equation formed byy=acosx+bsinx+ 4 whereaandbare arbitraryconstants is :a)(d2y/dx2) +y= 0b)(d2y/dx2) –y= 0c)(d2y/dx2) +y= 4d)(d2y/dx2) –y= 4Correct answer is option 'C'. Can you explain this answer?.
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