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The plate load test was conducted on a clayey strata by using a plate of 0.3m × 0.3 m dimensions, and the ultimate load per unit area for the plate was found to be 180 kPa. The ultimate bearing capacity (in kPa) of a 2 m wide square footing would be  
  • a)
    27
  • b)
    180
  • c)
    1200
  • d)
    2000 
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The plate load test was conducted on a clayey strata by using a plate ...
In plate load test,
The ultimate bearing capacity does not depends upon width of footing 
quf = qup = 180 kPa
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The plate load test was conducted on a clayey strata by using a plate ...
The ultimate bearing capacity of a square footing can be determined by using the plate load test results. In this case, the plate load test was conducted on a clayey strata using a plate with dimensions of 0.3m x 0.3m. The ultimate load per unit area for the plate was found to be 180 kPa.

To calculate the ultimate bearing capacity of a 2m wide square footing, we can use the concept of similarity. The ultimate bearing capacity of a footing can be expressed as:

qult = qpl * (Df / Dp)^2

Where:
qult = ultimate bearing capacity of the footing
qpl = ultimate load per unit area for the plate
Df = width of the footing
Dp = width of the plate

In this case, the width of the footing (Df) is 2m and the width of the plate (Dp) is 0.3m. Substituting these values into the equation, we can calculate the ultimate bearing capacity of the footing:

qult = 180 kPa * (2m / 0.3m)^2
qult = 180 kPa * (6.67)^2
qult = 180 kPa * 44.45
qult = 7990 kPa

Therefore, the ultimate bearing capacity of the 2m wide square footing is 7990 kPa.

However, the correct answer given is option 'B', which states that the ultimate bearing capacity is 180 kPa. This seems to be incorrect based on the calculations above. It is possible that there is a mistake in the provided answer options, as the calculated value of 7990 kPa aligns with the calculations performed.
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The plate load test was conducted on a clayey strata by using a plate of 0.3m × 0.3 m dimensions, and the ultimate load per unit area for the plate was found to be 180 kPa. The ultimate bearing capacity (in kPa) of a 2 m wide square footing would be a)27b)180c)1200d)2000Correct answer is option 'B'. Can you explain this answer?
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