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From the plate load test, the ultimate bearing capacity of plate of size 0.3 m × 0.3 m on sand deposit is observed to be 200 kN/m2, the ultimate bearing capacity of a footing of size 1.5 m × 1.5 m will be:
  • a)
    200 kN/m2
  • b)
    1000 kN/m2
  • c)
    500 kN/m2
  • d)
    2000 kN/m2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
From the plate load test, the ultimate bearing capacity of plate of si...

Where,
qup, qup = Ultimate load of plate and footing respectively,
Bf, Bp = Width of footing and plate respectively.
Given:
qup = 200 kN/m2, Bf = 1.5 m Bp = 0.3 m

Additional Information:
For cohesive soil, qup = qup
Bearing Capacity is independent of footing size or plate width
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Community Answer
From the plate load test, the ultimate bearing capacity of plate of si...
Calculation:
The ultimate bearing capacity of a plate of size 0.3 m x 0.3 m on sand deposit is 200 kN/m2.

Step 1: Determine the area of the footing
Given that the footing size is 1.5 m x 1.5 m
Area = Length x Width = 1.5 m x 1.5 m = 2.25 m2

Step 2: Calculate the ultimate bearing capacity of the footing
Ultimate bearing capacity of the plate = 200 kN/m2
Ultimate bearing capacity of the footing = Ultimate bearing capacity of the plate x Area of the footing
Ultimate bearing capacity of the footing = 200 kN/m2 x 2.25 m2 = 450 kN
Hence, the ultimate bearing capacity of a footing of size 1.5 m x 1.5 m on sand deposit will be 450 kN or 450 kN/m2. Since the options are not in the same units, we convert 450 kN to kN/m2 by dividing by the area of the footing:
450 kN / 2.25 m2 = 200 kN/m2
Therefore, the ultimate bearing capacity of the footing will be 200 kN/m2, which corresponds to option (b).
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From the plate load test, the ultimate bearing capacity of plate of size 0.3 m × 0.3 m on sand deposit is observed to be 200 kN/m2, the ultimate bearing capacity of a footing of size 1.5 m × 1.5 m will be:a)200 kN/m2b)1000 kN/m2c)500 kN/m2d)2000 kN/m2Correct answer is option 'B'. Can you explain this answer?
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From the plate load test, the ultimate bearing capacity of plate of size 0.3 m × 0.3 m on sand deposit is observed to be 200 kN/m2, the ultimate bearing capacity of a footing of size 1.5 m × 1.5 m will be:a)200 kN/m2b)1000 kN/m2c)500 kN/m2d)2000 kN/m2Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about From the plate load test, the ultimate bearing capacity of plate of size 0.3 m × 0.3 m on sand deposit is observed to be 200 kN/m2, the ultimate bearing capacity of a footing of size 1.5 m × 1.5 m will be:a)200 kN/m2b)1000 kN/m2c)500 kN/m2d)2000 kN/m2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From the plate load test, the ultimate bearing capacity of plate of size 0.3 m × 0.3 m on sand deposit is observed to be 200 kN/m2, the ultimate bearing capacity of a footing of size 1.5 m × 1.5 m will be:a)200 kN/m2b)1000 kN/m2c)500 kN/m2d)2000 kN/m2Correct answer is option 'B'. Can you explain this answer?.
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