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 If the flux linkage in coil 1 is 3Wb-t and it has 500 turns and the current in coil 2 is 2A, calculate the mutual inductance.
  • a)
    750H
  • b)
    500H
  • c)
    450H
  • d)
    900H
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If the flux linkage in coil 1 is 3Wb-t and it has 500 turns and the cu...
We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
M=3*500/2=750H.
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Most Upvoted Answer
If the flux linkage in coil 1 is 3Wb-t and it has 500 turns and the cu...
Given:
- Flux linkage in coil 1 (N1Φ) = 3 Wb-t
- Number of turns in coil 1 (N1) = 500
- Current in coil 2 (i2) = 2 A

Formula:
The mutual inductance (M) between two coils is given by the formula:

M = N1Φ / i2

Calculation:
Substituting the given values in the formula, we get:

M = N1Φ / i2
M = 3 Wb-t * 500 / 2 A
M = 750 H

Therefore, the mutual inductance between the two coils is 750 H, which is option A.
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If the flux linkage in coil 1 is 3Wb-t and it has 500 turns and the current in coil 2 is 2A, calculate the mutual inductance.a)750Hb)500Hc)450Hd)900HCorrect answer is option 'A'. Can you explain this answer?
Question Description
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