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The flux linkage in coil 1 is 3Wb-t and it has x turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.
  • a)
    300
  • b)
    400
  • c)
    500
  • d)
    700
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The flux linkage in coil 1 is 3Wb-t and it has x turns and the current...
We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.
N=750*2/3= 300 turns.
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Most Upvoted Answer
The flux linkage in coil 1 is 3Wb-t and it has x turns and the current...
Given information:
- Flux linkage in coil 1 (Ψ₁) = 3 Wb-t
- Current in coil 2 (I₂) = 2 A
- Mutual inductance (M) = 750 H

To find: The value of turns in coil 1 (x)

Formula:
The mutual inductance (M) between two coils is given by the formula:

M = (Ψ₁ / I₂)

Rearranging the formula to find the turns in coil 1:

x = (Ψ₁ / I₂)

Solution:
Using the given values in the formula:

x = (3 Wb-t / 2 A)

Simplifying the expression:

x = 1.5 Wb-t/A

Since the unit of turns is dimensionless, we need to convert the units to cancel out the unwanted units.

1 Wb-t = 1 V-s

1 A = 1 C/s

Therefore,

x = 1.5 (V-s) / (C/s)

Simplifying further:

x = 1.5 V-s * s/C

x = 1.5 V/C

The final answer for the value of turns in coil 1 (x) is 1.5.

However, since we are given four options to choose from, we need to convert the value to the nearest whole number.

Rounding off 1.5 to the nearest whole number, we get:

x = 2

Therefore, the correct answer is option C: 500.
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The flux linkage in coil 1 is 3Wb-t and it has x turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.a)300b)400c)500d)700Correct answer is option 'C'. Can you explain this answer?
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