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Answer the question based on the following information.
The city K is 30 Km to the southeast of Z while Y is 50 Km to the northwest of K. Also , H is 38 Km to the southeast of Y. L lies in the direct route between Y and K and its distance from H is 14 Km. G also lies on this route and is exactly midway between L and Y. 
Q. A car starting from K at 9 am and running at a constant speed towards Y reaches H at 9.24 am and then reaches G at
  • a)
    9.18 am
  • b)
    10.16 am
  • c)
    10.36 am
  • d)
    10.42 am
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Answer the question based on the following information.The city K is 3...
The car covers K to h - a distance of 12 kms in 24 minutes according to the figure (starting at 9 am and reaching at 9 : 24 am). From H to G, the distance is 26 kms.
(18 H to Z + 8 Z to G). Since the car has covered 12 kms in 24 minutes, it is obvious that it is taking 2 minutes to cover 1 km.
We also know that the sped of the car is constant throughout.
Hence, the car would take another 52 minutes to cover the 26 kms distance between H to G This means that the car would reach G at 10:16 am(52 minutes after 9:24 am).
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Most Upvoted Answer
Answer the question based on the following information.The city K is 3...
Given Information:
- City K is 30 Km southeast of Z.
- City Y is 50 Km northwest of K.
- City H is 38 Km southeast of Y.
- L lies in the direct route between Y and K and its distance from H is 14 Km.
- G lies on the same route and is exactly midway between L and Y.

To find: The time at which the car reaches G.

Solution:
Step 1: Draw a diagram representing the given information.

Z
|
|
K
|
|
L----G----Y
|
|
H

Step 2: Calculate the distances between the given cities.
- Distance between K and Y = 30 + 50 = 80 Km
- Distance between Y and H = 38 Km
- Distance between Y and L = Distance between K and L = (80/2) = 40 Km
- Distance between L and H = 14 Km

Step 3: Calculate the time taken by the car to reach H.
- The car covers the distance between K and H = (30 + 40 + 38) = 108 Km
- Time taken to cover 108 Km at a constant speed = (24/100)*60 = 14.4 minutes = 9:14 am + 14 minutes
- Therefore, the car reaches H at 9:24 am.

Step 4: Calculate the time taken by the car to reach G.
- Distance between Y and G = (40/2) = 20 Km
- Total distance covered by the car = Distance between K and H + Distance between H and G = 108 + 20 = 128 Km
- Time taken to cover 128 Km at a constant speed = (128/80)*60 = 96 minutes = 1 hour 36 minutes
- Therefore, the car reaches G at 9:24 am + 1 hour 36 minutes = 10:16 am.

Therefore, the correct answer is option B) 10:16 am.
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Answer the question based on the following information.The city K is 30 Km to the southeast of Z while Y is 50 Km to the northwest of K. Also , H is 38 Km to the southeast of Y. L lies in the direct route between Y and K and its distance from H is 14 Km. G also lies on this route and is exactly midway between L and Y.Q. A car starting from K at 9 am and running at a constant speed towards Y reaches H at 9.24 am and then reaches G ata)9.18 amb)10.16 amc)10.36 amd)10.42 amCorrect answer is option 'B'. Can you explain this answer?
Question Description
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