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If sinθ+cosecθ=2, the value of sin2 θ+cosec2 θ is :
  • a)
    1
  • b)
    4
  • c)
    2
  • d)
    3
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If sinθ+cosecθ=2, the value of sin2 θ+cosec2 θ...
Given:
sinθ + cosecθ = 2

To Find:
sin^2 θ + cosec^2 θ

Solution:

Step 1: Simplify the given equation
sinθ + cosecθ = 2
(sinθ)(cosecθ) + 1 = 2
sinθ(cosecθ) = 1

Step 2: Find sin^2 θ and cosec^2 θ
sin^2 θ = (sinθ)^2 = (1/(cosecθ))^2 = 1/(cosecθ)^2 = 1/(1/sinθ)^2 = sin^2 θ
cosec^2 θ = (cosecθ)^2 = 1/(sinθ)^2 = 1/(1/cosecθ)^2 = cosec^2 θ

Step 3: Find sin^2 θ + cosec^2 θ
sin^2 θ + cosec^2 θ = sin^2 θ + 1/(sinθ)^2 = sin^2 θ + 1/sin^2 θ
Since sin^2 θ = sinθ and 1/sin^2 θ = cosecθ, we substitute these values:
sin^2 θ + cosec^2 θ = sinθ + cosecθ = 2
Therefore, sin^2 θ + cosec^2 θ = 2.
Therefore, the correct answer is option 'C'.
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Community Answer
If sinθ+cosecθ=2, the value of sin2 θ+cosec2 θ...
Square the given equation, then

(sin x + cosec x)^2 = 4
sin^2 x + cosec^2 x + 2sin x cosecx =4
sin^2 x + cosec^2 x + 2 = 4
sin^2 x + cosec^2 x = 2

Option C
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If sinθ+cosecθ=2, the value of sin2 θ+cosec2 θ is :a)1b)4c)2d)3Correct answer is option 'C'. Can you explain this answer?
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