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An electrostatic precipitator (ESP) with 5600 m2 of collector plate area is 96 percent efficient in treating 185 m3/s of flue gas from a 200 MW thermal power plant. It was found that in order to achieve 97 percent efficiency, the collector plate area should be 6100 m2. In order to increase the efficiency to 99 percent, the ESP collector plate area (expressed in m2) would be ______Correct answer is between '8000,8040'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared
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An electrostatic precipitator (ESP) with 5600 m2 of collector plate area is 96 percent efficient in treating 185 m3/s of flue gas from a 200 MW thermal power plant. It was found that in order to achieve 97 percent efficiency, the collector plate area should be 6100 m2. In order to increase the efficiency to 99 percent, the ESP collector plate area (expressed in m2) would be ______Correct answer is between '8000,8040'. Can you explain this answer?, a detailed solution for An electrostatic precipitator (ESP) with 5600 m2 of collector plate area is 96 percent efficient in treating 185 m3/s of flue gas from a 200 MW thermal power plant. It was found that in order to achieve 97 percent efficiency, the collector plate area should be 6100 m2. In order to increase the efficiency to 99 percent, the ESP collector plate area (expressed in m2) would be ______Correct answer is between '8000,8040'. Can you explain this answer? has been provided alongside types of An electrostatic precipitator (ESP) with 5600 m2 of collector plate area is 96 percent efficient in treating 185 m3/s of flue gas from a 200 MW thermal power plant. It was found that in order to achieve 97 percent efficiency, the collector plate area should be 6100 m2. In order to increase the efficiency to 99 percent, the ESP collector plate area (expressed in m2) would be ______Correct answer is between '8000,8040'. Can you explain this answer? theory, EduRev gives you an
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