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If the intensity of magnetic field is 100T, the length of the conductor is 3m and the current in the conductor is 10A, calculate the magnitude of force perpendicular to the electric field.
  • a)
    300N
  • b)
    30N
  • c)
    30kN
  • d)
    3kN
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If the intensity of magnetic field is 100T, the length of the conducto...
The formula for calculating the value of the force which is perpendicular to the electric field is:
F=Bil
Substituting the values from the question, we get F=3kN.
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Most Upvoted Answer
If the intensity of magnetic field is 100T, the length of the conducto...
Given:
Intensity of magnetic field (B) = 100T
Length of the conductor (l) = 3m
Current in the conductor (I) = 10A

To find: Magnitude of force (F) perpendicular to the electric field

Formula: F = BIL

Calculation:
Substituting the given values in the formula, we get
F = 100 x 3 x 10
F = 3000N

Therefore, the magnitude of force perpendicular to the electric field is 3kN (Option D).

Explanation:

In this question, we are given a conductor with a length of 3m and a current of 10A passing through it. The conductor is placed in a magnetic field with an intensity of 100T.

When a current-carrying conductor is placed in a magnetic field, it experiences a force perpendicular to the direction of the magnetic field and the current. This force is given by the formula F = BIL, where F is the force, B is the magnetic field intensity, I is the current passing through the conductor, and L is the length of the conductor.

Substituting the given values in the formula, we get F = 100 x 3 x 10 = 3000N. Therefore, the magnitude of force perpendicular to the electric field is 3kN (Option D).

Overall, this question tests the understanding of the relationship between magnetic fields, current, and force.
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