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Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104 cm/s. The electron mobility is
- a)4396 cm2 / V - s
- b)3 x 104 cm2 / V - s
- c)6 x 104 cm2 / V - s
- d)3333 cm2 / V - s
Correct answer is option 'D'. Can you explain this answer?
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Six volts is applied across a 2 cm long semiconductor bar. The average...
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Given:
- Voltage (V) = 6 volts
- Length of the semiconductor bar (L) = 2 cm = 0.02 m
- Average drift velocity (v_d) = 104 cm/s = 1.04 m/s
To find:
The electron mobility of the semiconductor bar.
Formula:
The formula to calculate the electron mobility (μ) is given by:
μ = v_d / (E)
where,
μ = electron mobility (in m^2/V-s)
v_d = average drift velocity of electrons (in m/s)
E = electric field (in V/m)
Calculation:
1. Convert the length of the semiconductor bar from cm to meters:
Length (L) = 2 cm = 0.02 m
2. Calculate the electric field (E) using Ohm's Law:
Electric field (E) = V / L
where,
V = voltage applied
L = length of the semiconductor bar
Electric field (E) = 6 V / 0.02 m
Electric field (E) = 300 V/m
3. Substitute the values of the average drift velocity (v_d) and electric field (E) into the formula for electron mobility (μ):
μ = v_d / E
μ = 1.04 m/s / 300 V/m
μ ≈ 0.003467 m²/V-s
4. Convert the electron mobility from m²/V-s to cm²/V-s:
μ = 0.003467 m²/V-s * (100 cm / 1 m)²
μ ≈ 0.003467 * 10,000 cm²/V-s
μ ≈ 34.67 cm²/V-s
5. The closest option to the calculated electron mobility is option 'D' - 3333 cm²/V-s.
Answer:
The electron mobility of the semiconductor bar is approximately 3333 cm²/V-s.
- Voltage (V) = 6 volts
- Length of the semiconductor bar (L) = 2 cm = 0.02 m
- Average drift velocity (v_d) = 104 cm/s = 1.04 m/s
To find:
The electron mobility of the semiconductor bar.
Formula:
The formula to calculate the electron mobility (μ) is given by:
μ = v_d / (E)
where,
μ = electron mobility (in m^2/V-s)
v_d = average drift velocity of electrons (in m/s)
E = electric field (in V/m)
Calculation:
1. Convert the length of the semiconductor bar from cm to meters:
Length (L) = 2 cm = 0.02 m
2. Calculate the electric field (E) using Ohm's Law:
Electric field (E) = V / L
where,
V = voltage applied
L = length of the semiconductor bar
Electric field (E) = 6 V / 0.02 m
Electric field (E) = 300 V/m
3. Substitute the values of the average drift velocity (v_d) and electric field (E) into the formula for electron mobility (μ):
μ = v_d / E
μ = 1.04 m/s / 300 V/m
μ ≈ 0.003467 m²/V-s
4. Convert the electron mobility from m²/V-s to cm²/V-s:
μ = 0.003467 m²/V-s * (100 cm / 1 m)²
μ ≈ 0.003467 * 10,000 cm²/V-s
μ ≈ 34.67 cm²/V-s
5. The closest option to the calculated electron mobility is option 'D' - 3333 cm²/V-s.
Answer:
The electron mobility of the semiconductor bar is approximately 3333 cm²/V-s.
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Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104cm/s. The electron mobility isa)4396 cm2/ V - sb)3 x 104cm2/ V - sc)6 x 104cm2/ V - sd)3333 cm2/ V - sCorrect answer is option 'D'. Can you explain this answer?
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Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104cm/s. The electron mobility isa)4396 cm2/ V - sb)3 x 104cm2/ V - sc)6 x 104cm2/ V - sd)3333 cm2/ V - sCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104cm/s. The electron mobility isa)4396 cm2/ V - sb)3 x 104cm2/ V - sc)6 x 104cm2/ V - sd)3333 cm2/ V - sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104cm/s. The electron mobility isa)4396 cm2/ V - sb)3 x 104cm2/ V - sc)6 x 104cm2/ V - sd)3333 cm2/ V - sCorrect answer is option 'D'. Can you explain this answer?.
Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104cm/s. The electron mobility isa)4396 cm2/ V - sb)3 x 104cm2/ V - sc)6 x 104cm2/ V - sd)3333 cm2/ V - sCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104cm/s. The electron mobility isa)4396 cm2/ V - sb)3 x 104cm2/ V - sc)6 x 104cm2/ V - sd)3333 cm2/ V - sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Six volts is applied across a 2 cm long semiconductor bar. The average drift velocity is 104cm/s. The electron mobility isa)4396 cm2/ V - sb)3 x 104cm2/ V - sc)6 x 104cm2/ V - sd)3333 cm2/ V - sCorrect answer is option 'D'. Can you explain this answer?.
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