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Find the electric field applied on a system with electrons having a velocity 5m/s subjected to a magnetic flux of 3.6 units.
- a)15
- b)18
- c)1.38
- d)0.72
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Find the electric field applied on a system with electrons having a ve...
Answer: b
Explanation: The electric field intensity is the product of the velocity and the magnetic flux density. Thus E = v x B, on substituting v = 5 and B = 3.6, we get E = 5 x 3.6 = 18 units.
Explanation: The electric field intensity is the product of the velocity and the magnetic flux density. Thus E = v x B, on substituting v = 5 and B = 3.6, we get E = 5 x 3.6 = 18 units.
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Find the electric field applied on a system with electrons having a ve...
Calculating the Electric Field on Electrons
Electric field applied on a system with electrons moving at a velocity and subjected to a magnetic flux can be calculated using the formula:
\[ E = \frac{B \times v}{c} \]
Where:
- \( E \) = Electric field applied on the system
- \( B \) = Magnetic flux density
- \( v \) = Velocity of the electrons
- \( c \) = Speed of light
Given Values:
- Velocity (\( v \)) = 5m/s
- Magnetic flux density (\( B \)) = 3.6 units
- Speed of light (\( c \)) = \( 3 \times 10^8 \) m/s
Calculating the Electric Field:
\[ E = \frac{3.6 \times 5}{3 \times 10^8} \]
\[ E = \frac{18}{3 \times 10^8} \]
\[ E = 6 \times 10^{-8} \]
\[ E = 18 \times 10^{-9} \]
\[ E = 18 \times 10^{-9} \times 10^9 \]
\[ E = 18 \, N/C \]
Therefore, the electric field applied on the system with electrons is 18 N/C. Hence, the correct answer is option B.
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