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A diffraction grating of length 3.5 x 10-2 m is illuminated by a light of wavelength 4997A0 & 5003A0. The maximum size of the grating element d (in μm) required to resolve the two wavelength in the first order _____:-
    Correct answer is '42'. Can you explain this answer?
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    A diffraction grating of length 3.5 x 10-2 m is illuminated by a light...
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    A diffraction grating of length 3.5 x 10-2 m is illuminated by a light...
    To calculate the number of lines in the diffraction grating, we can use the formula:

    number of lines = length / distance between lines

    Given:
    length = 3.5 x 10^-2 m
    wavelength = 4997 Å (1 Å = 10^-10 m)

    First, we need to convert the wavelength from Å to meters:
    wavelength = 4997 x 10^-10 m

    Now we can substitute the values into the formula:
    number of lines = (3.5 x 10^-2 m) / (4997 x 10^-10 m)

    To divide these two numbers, we can divide the numerator by the denominator and multiply by 10^10:
    number of lines = (3.5 x 10^-2 m) * (10^10 m / 4997 x 10^-10 m)
    number of lines = (3.5 x 10^-2) * (10^10 / 4997)

    Performing the calculation:
    number of lines ≈ 7000.7

    Therefore, the number of lines in the diffraction grating is approximately 7000.7.
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    A diffraction grating of length 3.5 x 10-2 m is illuminated by a light of wavelength 4997A0 & 5003A0. The maximum size of the grating element d (inμm) required to resolve the two wavelength in the first order _____:-Correct answer is '42'. Can you explain this answer?
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