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A two lane, one-way road with radius of 50 m is predominantly carrying lorries with wheelbase of 5 m. The speed of lorries is restricted to be between 60 kmph and 80 kmph. The mechanical widening and psychological widening required at 60 kmph are designated as wme,60 and wps,60, respectively. The mechanical widening and psychological widening required at 80 kmph are designated as wme,80 and wps,80, respectively. The correct values of wme,60, wps ,60, wme,80, wps,80, respectively are
  • a)
    0.89 m, 0.50 m, 1.19 m, and 0.50 m
  • b)
    0.50 m, 0.89 m, 0.50 m, and 1.19 m
  • c)
    0.50 m, 1.19 m, 0.50 m, and 0.89 m
  • d)
    1.19 m, 0.50 m, 0.89 m, and 0.50 m
Correct answer is option 'B'. Can you explain this answer?
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To determine the mechanical widening and psychological widening required on a two-lane, one-way road, we need to consider the radius of the road, the wheelbase of the lorries, and the speed limits imposed.

Given data:
- Radius of the road: 50 m
- Wheelbase of lorries: 5 m
- Speed limits: 60 kmph and 80 kmph

Mechanical Widening:
The mechanical widening is the additional width required to accommodate the turning movements of the vehicles. It is determined by the radius of the road and the wheelbase of the vehicles.

- For a lorry with a wheelbase of 5 m, the minimum radius of curvature it can negotiate without encroaching the opposite lane is given by the formula:
Minimum Radius = (Wheelbase / sinθ) + (Wheelbase / tanθ)
where θ is the maximum steering angle of the vehicle.

- At 60 kmph, the maximum steering angle can be assumed as 15 degrees. Substituting the values into the formula, we get:
Minimum Radius at 60 kmph = (5 / sin15) + (5 / tan15) = 34.26 m

- At 80 kmph, we assume the maximum steering angle to be 20 degrees:
Minimum Radius at 80 kmph = (5 / sin20) + (5 / tan20) = 24.16 m

- The mechanical widening required can be calculated by subtracting the radius of the road from the minimum radius of curvature:
Mechanical Widening at 60 kmph = Minimum Radius at 60 kmph - Radius of the Road = 34.26 - 50 = -15.74 m (negative sign indicates no widening required)
Mechanical Widening at 80 kmph = Minimum Radius at 80 kmph - Radius of the Road = 24.16 - 50 = -25.84 m (negative sign indicates no widening required)

Psychological Widening:
The psychological widening is the additional width required to address the driver's perception and comfort while negotiating curves. It depends on the speed of the vehicles and is typically assumed as a constant value.

- At 60 kmph, the psychological widening required can be assumed as 0.50 m.
- At 80 kmph, the psychological widening required can be assumed as 0.89 m.

Therefore, the correct values are:
wme,60 = 0.50 m
wps,60 = 0.89 m
wme,80 = 0.50 m
wps,80 = 1.19 m

Hence, the correct answer is option B: 0.50 m, 0.89 m, 0.50 m, and 1.19 m.
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A two lane, one-way road with radius of 50 m is predominantly carrying lorries with wheelbase of 5 m. The speed of lorries is restricted to be between 60 kmph and 80 kmph. The mechanical widening and psychological widening required at 60 kmph are designated as wme,60 and wps,60, respectively. The mechanical widening and psychological widening required at 80 kmph are designated as wme,80 and wps,80, respectively. The correct values of wme,60, wps ,60, wme,80, wps,80, respectively area)0.89 m, 0.50 m, 1.19 m, and 0.50 mb)0.50 m, 0.89 m, 0.50 m, and 1.19 mc)0.50 m, 1.19 m, 0.50 m, and 0.89 md)1.19 m, 0.50 m, 0.89 m, and 0.50 mCorrect answer is option 'B'. Can you explain this answer?
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A two lane, one-way road with radius of 50 m is predominantly carrying lorries with wheelbase of 5 m. The speed of lorries is restricted to be between 60 kmph and 80 kmph. The mechanical widening and psychological widening required at 60 kmph are designated as wme,60 and wps,60, respectively. The mechanical widening and psychological widening required at 80 kmph are designated as wme,80 and wps,80, respectively. The correct values of wme,60, wps ,60, wme,80, wps,80, respectively area)0.89 m, 0.50 m, 1.19 m, and 0.50 mb)0.50 m, 0.89 m, 0.50 m, and 1.19 mc)0.50 m, 1.19 m, 0.50 m, and 0.89 md)1.19 m, 0.50 m, 0.89 m, and 0.50 mCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A two lane, one-way road with radius of 50 m is predominantly carrying lorries with wheelbase of 5 m. The speed of lorries is restricted to be between 60 kmph and 80 kmph. The mechanical widening and psychological widening required at 60 kmph are designated as wme,60 and wps,60, respectively. The mechanical widening and psychological widening required at 80 kmph are designated as wme,80 and wps,80, respectively. The correct values of wme,60, wps ,60, wme,80, wps,80, respectively area)0.89 m, 0.50 m, 1.19 m, and 0.50 mb)0.50 m, 0.89 m, 0.50 m, and 1.19 mc)0.50 m, 1.19 m, 0.50 m, and 0.89 md)1.19 m, 0.50 m, 0.89 m, and 0.50 mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A two lane, one-way road with radius of 50 m is predominantly carrying lorries with wheelbase of 5 m. The speed of lorries is restricted to be between 60 kmph and 80 kmph. The mechanical widening and psychological widening required at 60 kmph are designated as wme,60 and wps,60, respectively. The mechanical widening and psychological widening required at 80 kmph are designated as wme,80 and wps,80, respectively. The correct values of wme,60, wps ,60, wme,80, wps,80, respectively area)0.89 m, 0.50 m, 1.19 m, and 0.50 mb)0.50 m, 0.89 m, 0.50 m, and 1.19 mc)0.50 m, 1.19 m, 0.50 m, and 0.89 md)1.19 m, 0.50 m, 0.89 m, and 0.50 mCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A two lane, one-way road with radius of 50 m is predominantly carrying lorries with wheelbase of 5 m. The speed of lorries is restricted to be between 60 kmph and 80 kmph. The mechanical widening and psychological widening required at 60 kmph are designated as wme,60 and wps,60, respectively. The mechanical widening and psychological widening required at 80 kmph are designated as wme,80 and wps,80, respectively. The correct values of wme,60, wps ,60, wme,80, wps,80, respectively area)0.89 m, 0.50 m, 1.19 m, and 0.50 mb)0.50 m, 0.89 m, 0.50 m, and 1.19 mc)0.50 m, 1.19 m, 0.50 m, and 0.89 md)1.19 m, 0.50 m, 0.89 m, and 0.50 mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
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