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The magnetic field of the solenoid is 18.84mT, the number of turns per unit length is 500 turns per metre. Calculate the current if the core is air.
  • a)
    300A
  • b)
    30A
  • c)
    3A
  • d)
    300mA
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The magnetic field of the solenoid is 18.84mT, the number of turns per...
 The magnetic field in a solenoid is given by:
B=μnI
Substituting the values in the given values in the equation, I=30A.
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Most Upvoted Answer
The magnetic field of the solenoid is 18.84mT, the number of turns per...
Given data:
Magnetic field of the solenoid (B) = 18.84 mT = 0.01884 T
Number of turns per unit length (n) = 500 turns/m
Core material: Air

Calculating the current:
The magnetic field inside a solenoid can be calculated using the formula:
B = μ₀ * n * I
Where:
B = Magnetic field (T)
μ₀ = Permeability of free space = 4π x 10^-7 Tm/A
n = Number of turns per unit length (turns/m)
I = Current (A)

Substitute the given values into the formula:
0.01884 = 4π x 10^-7 * 500 * I

Solving for current (I):
I = 0.01884 / (4π x 10^-7 x 500)
I ≈ 30 A
Therefore, the current flowing through the solenoid when the core is air is 30 A, which corresponds to option B.
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