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Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]
- a)Metal sulphides are thermodynamically more stablethan CS2
- b)CO2 is thermodynamically more stable than CS2
- c)Metal sulphides are less stable than the correspondingoxides
- d)CO2 is more volatile than CS2
Correct answer is option 'C'. Can you explain this answer?
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Which of the following factors is of no significance forroasting sulph...
Hence CO2 is more stable than CS2 while MS are more stable than MO.
Answer : Metal sulphide are less stable than the corresponding oxides
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Which of the following factors is of no significance forroasting sulph...
Explanation:
Roasting is a process in which a sulphide ore is heated in the presence of excess air or oxygen to convert the sulphide into its oxide form. This process is used to extract metals from their sulphide ores. However, not subjecting the sulphide ores to carbon reduction directly means that carbon (C) is not used to reduce the sulphide ore to its metal form.
The question asks for the factor that is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly. Let's analyze each option:
a) Metal sulphides are thermodynamically more stable than CS2: This statement is true. Metal sulphides are generally more stable than carbon disulphide (CS2). Therefore, roasting the sulphide ore to convert it into its oxide form is a preferred method over carbon reduction.
b) CO2 is thermodynamically more stable than CS2: This statement is true. Carbon dioxide (CO2) is thermodynamically more stable than carbon disulphide (CS2). This means that during the roasting process, the carbon disulphide will be converted into carbon dioxide, which is a more stable compound.
c) Metal sulphides are less stable than the corresponding oxides: This statement is also true. Metal sulphides are generally less stable than their corresponding oxides. Therefore, roasting the sulphide ore to convert it into its oxide form is a preferred method over carbon reduction.
d) CO2 is more volatile than CS2: This statement is true. Carbon dioxide (CO2) is more volatile than carbon disulphide (CS2). This means that during the roasting process, the carbon disulphide will be converted into carbon dioxide, which is a more volatile compound.
Conclusion:
From the given options, option c) Metal sulphides are less stable than the corresponding oxides is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly. This is because metal sulphides are indeed less stable than their corresponding oxides, and this factor is one of the reasons why roasting is preferred over carbon reduction for extracting metals from their sulphide ores.
Roasting is a process in which a sulphide ore is heated in the presence of excess air or oxygen to convert the sulphide into its oxide form. This process is used to extract metals from their sulphide ores. However, not subjecting the sulphide ores to carbon reduction directly means that carbon (C) is not used to reduce the sulphide ore to its metal form.
The question asks for the factor that is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly. Let's analyze each option:
a) Metal sulphides are thermodynamically more stable than CS2: This statement is true. Metal sulphides are generally more stable than carbon disulphide (CS2). Therefore, roasting the sulphide ore to convert it into its oxide form is a preferred method over carbon reduction.
b) CO2 is thermodynamically more stable than CS2: This statement is true. Carbon dioxide (CO2) is thermodynamically more stable than carbon disulphide (CS2). This means that during the roasting process, the carbon disulphide will be converted into carbon dioxide, which is a more stable compound.
c) Metal sulphides are less stable than the corresponding oxides: This statement is also true. Metal sulphides are generally less stable than their corresponding oxides. Therefore, roasting the sulphide ore to convert it into its oxide form is a preferred method over carbon reduction.
d) CO2 is more volatile than CS2: This statement is true. Carbon dioxide (CO2) is more volatile than carbon disulphide (CS2). This means that during the roasting process, the carbon disulphide will be converted into carbon dioxide, which is a more volatile compound.
Conclusion:
From the given options, option c) Metal sulphides are less stable than the corresponding oxides is of no significance for roasting sulphide ores to the oxides and not subjecting the sulphide ores to carbon reduction directly. This is because metal sulphides are indeed less stable than their corresponding oxides, and this factor is one of the reasons why roasting is preferred over carbon reduction for extracting metals from their sulphide ores.
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Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer?
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Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer?.
Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer?.
Solutions for Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Which of the following factors is of no significance forroasting sulphide ores to the oxides and not subjecting thesulphide ores to carbon reduction directly? [2008]a)Metal sulphides are thermodynamically more stablethan CS2b)CO2 is thermodynamically more stable than CS2c)Metal sulphides are less stable than the correspondingoxidesd)CO2 is more volatile than CS2Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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