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The input impedance of short-circuited line of length l where λ/4 < l < λ/2, is
- a)resistive
- b)inductive
- c)capacitive
- d)none of the above
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The input impedance of short-circuited line of length l where λ/4 <...
l < λ/4, ZL = 0
, if Zd comes +j kZC then inductive, If Zd comes -j kZC then capacitive.
for 0 ≤ l ≤ 1/4, λ ≤ l ≤ 3λ/4 will be inductive.
Most Upvoted Answer
The input impedance of short-circuited line of length l where λ/4 <...
The input impedance of a short-circuited transmission line of length l, where λ/4 is the wavelength, can be calculated using the formula:
Zin = jZ0 * tan(βl)
Where Zin is the input impedance, Z0 is the characteristic impedance of the transmission line, β is the propagation constant (2π/λ), and l is the length of the transmission line.
For a short-circuited line of length λ/4, the length l would be equal to λ/4. Therefore, the input impedance can be calculated as:
Zin = jZ0 * tan(β * (λ/4))
Since λ/4 is a quarter-wavelength, the tangent of βl will be infinite, resulting in an open circuit. Therefore, the input impedance of a short-circuited line of length λ/4 is an open circuit.
Zin = jZ0 * tan(βl)
Where Zin is the input impedance, Z0 is the characteristic impedance of the transmission line, β is the propagation constant (2π/λ), and l is the length of the transmission line.
For a short-circuited line of length λ/4, the length l would be equal to λ/4. Therefore, the input impedance can be calculated as:
Zin = jZ0 * tan(β * (λ/4))
Since λ/4 is a quarter-wavelength, the tangent of βl will be infinite, resulting in an open circuit. Therefore, the input impedance of a short-circuited line of length λ/4 is an open circuit.
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