Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A hollow rectangular waveguide has dimensions...
Start Learning for Free
A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.
- a)49
- b)47.33
- c)50.33
- d)50
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A hollow rectangular waveguide has dimensions a = 2b. Calculate the am...
Since, wave is attenuated hence β = 0
and 
Take, dominant mode m = 1,
Take, dominant mode m = 1, n = 0
.Most Upvoted Answer
A hollow rectangular waveguide has dimensions a = 2b. Calculate the am...
To calculate the amount of attenuation in a hollow rectangular waveguide, we need to use the formula for attenuation in waveguides:
Attenuation = α × length
where α is the attenuation constant and length is the length of the waveguide.
The attenuation constant α can be calculated using the following formula:
α = (2πf√(με)) / β
where f is the frequency, μ is the permeability of free space, ε is the permittivity of free space, and β is the propagation constant.
The propagation constant β can be expressed as:
β = √(k^2 - (π/a)^2 - (π/b)^2)
where k is the wave number, given by:
k = ω√(με)
Given that a = 2b, we can substitute a = 2b into the formulas above to simplify the calculations.
Now, let's substitute the given values into the formulas:
a = 2b
b = 1 cm = 0.01 m
f = 3 GHz = 3 × 10^9 Hz
μ = 4π × 10^-7 Tm/A
ε = 8.854 × 10^-12 F/m
First, we need to calculate k:
k = ω√(με)
= 2πf√(με)
= 2π(3 × 10^9 Hz)√(4π × 10^-7 Tm/A)(8.854 × 10^-12 F/m)
≈ 2.674 × 10^7 rad/m
Next, we can calculate β:
β = √(k^2 - (π/a)^2 - (π/b)^2)
= √((2.674 × 10^7 rad/m)^2 - (π/(2b))^2 - (π/b)^2)
≈ 2.674 × 10^7 rad/m
Finally, we can calculate the attenuation constant α:
α = (2πf√(με)) / β
= (2π(3 × 10^9 Hz)√(4π × 10^-7 Tm/A)(8.854 × 10^-12 F/m)) / (2.674 × 10^7 rad/m)
≈ 47.33 Np/m
Therefore, the amount of attenuation is approximately 47.33 Np/m. Thus, the correct answer is option B.
Attenuation = α × length
where α is the attenuation constant and length is the length of the waveguide.
The attenuation constant α can be calculated using the following formula:
α = (2πf√(με)) / β
where f is the frequency, μ is the permeability of free space, ε is the permittivity of free space, and β is the propagation constant.
The propagation constant β can be expressed as:
β = √(k^2 - (π/a)^2 - (π/b)^2)
where k is the wave number, given by:
k = ω√(με)
Given that a = 2b, we can substitute a = 2b into the formulas above to simplify the calculations.
Now, let's substitute the given values into the formulas:
a = 2b
b = 1 cm = 0.01 m
f = 3 GHz = 3 × 10^9 Hz
μ = 4π × 10^-7 Tm/A
ε = 8.854 × 10^-12 F/m
First, we need to calculate k:
k = ω√(με)
= 2πf√(με)
= 2π(3 × 10^9 Hz)√(4π × 10^-7 Tm/A)(8.854 × 10^-12 F/m)
≈ 2.674 × 10^7 rad/m
Next, we can calculate β:
β = √(k^2 - (π/a)^2 - (π/b)^2)
= √((2.674 × 10^7 rad/m)^2 - (π/(2b))^2 - (π/b)^2)
≈ 2.674 × 10^7 rad/m
Finally, we can calculate the attenuation constant α:
α = (2πf√(με)) / β
= (2π(3 × 10^9 Hz)√(4π × 10^-7 Tm/A)(8.854 × 10^-12 F/m)) / (2.674 × 10^7 rad/m)
≈ 47.33 Np/m
Therefore, the amount of attenuation is approximately 47.33 Np/m. Thus, the correct answer is option B.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer?
Question Description
A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer?.
A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer?.
Solutions for A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A hollow rectangular waveguide has dimensions a = 2b. Calculate the amount of attenuation, if the frequency is 3 GHz, and b = 1 cm.a)49b)47.33c)50.33d)50Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup