Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A wave is propagated in a waveguide at freque...
Start Learning for Free
A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.
- a)4 cm
- b)1 cm
- c)2 cm
- d)8 cm
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A wave is propagated in a waveguide at frequency of 9 GHz and separati...
.Most Upvoted Answer
A wave is propagated in a waveguide at frequency of 9 GHz and separati...
Given:
- Frequency of the wave: 9 GHz
- Separation between walls: 2 cm
To find:
Cut off wavelength for the dominant mode.
Solution:
The cutoff wavelength is the minimum wavelength at which a particular mode can propagate in a waveguide. For a dominant mode, the wave travels in a straight line and bounces off the walls of the waveguide.
Step 1: Calculate the wavelength:
The wavelength of the wave can be calculated using the formula:
λ = c / f
where:
λ is the wavelength,
c is the speed of light (approximately 3 x 10^8 m/s),
f is the frequency of the wave.
Converting the frequency to Hz:
f = 9 GHz = 9 x 10^9 Hz
Plugging the values into the formula:
λ = (3 x 10^8 m/s) / (9 x 10^9 Hz)
Calculating the wavelength:
λ = 1/3 m = 0.333 m = 33.3 cm
Step 2: Calculate the cut off wavelength:
The cutoff wavelength for the dominant mode in a rectangular waveguide is given by the formula:
λc = 2a / sqrt(m^2 + n^2)
where:
a is the separation between the walls,
m and n are the mode numbers.
In the dominant mode, m = 1 and n = 0.
Plugging the values into the formula:
λc = 2(2 cm) / sqrt(1^2 + 0^2)
Calculating the cutoff wavelength:
λc = 4 cm
Therefore, the cut off wavelength for the dominant mode in the given waveguide is 4 cm (option A).
- Frequency of the wave: 9 GHz
- Separation between walls: 2 cm
To find:
Cut off wavelength for the dominant mode.
Solution:
The cutoff wavelength is the minimum wavelength at which a particular mode can propagate in a waveguide. For a dominant mode, the wave travels in a straight line and bounces off the walls of the waveguide.
Step 1: Calculate the wavelength:
The wavelength of the wave can be calculated using the formula:
λ = c / f
where:
λ is the wavelength,
c is the speed of light (approximately 3 x 10^8 m/s),
f is the frequency of the wave.
Converting the frequency to Hz:
f = 9 GHz = 9 x 10^9 Hz
Plugging the values into the formula:
λ = (3 x 10^8 m/s) / (9 x 10^9 Hz)
Calculating the wavelength:
λ = 1/3 m = 0.333 m = 33.3 cm
Step 2: Calculate the cut off wavelength:
The cutoff wavelength for the dominant mode in a rectangular waveguide is given by the formula:
λc = 2a / sqrt(m^2 + n^2)
where:
a is the separation between the walls,
m and n are the mode numbers.
In the dominant mode, m = 1 and n = 0.
Plugging the values into the formula:
λc = 2(2 cm) / sqrt(1^2 + 0^2)
Calculating the cutoff wavelength:
λc = 4 cm
Therefore, the cut off wavelength for the dominant mode in the given waveguide is 4 cm (option A).
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer?
Question Description
A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer?.
A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls find cut off wavelength for dominant mode.a)4 cmb)1 cmc)2 cmd)8 cmCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup