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A deposit of sand has a porosity of 35% and G = 2.7. The soil is dry in the top 2m depth, it has 20% moisture content in the next 2m depth and it is submerged below it. Find the effective stress at 5m below the ground surface.__________kN/m2.
(Important - Enter only the numerical value in the answer)
    Correct answer is '64.85'. Can you explain this answer?
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    Calculation of Effective Stress

    Given data:

    Porosity (n) = 35%

    Specific gravity (G) = 2.7

    Depth below ground surface (h) = 5m

    Moisture content (w) = 20%

    Formula used:

    Effective stress (σ') = Total stress (σ) - Pore water pressure (u)

    Pore water pressure (u) = h × γw

    Where, γw = unit weight of water = 9.81 kN/m³

    Total stress (σ) = γ × h

    Where, γ = effective unit weight of soil

    Effective unit weight of soil (γ) = (1 - n) × G × γw

    Calculation:

    Effective unit weight of soil (γ) = (1 - 0.35) × 2.7 × 9.81 = 15.96 kN/m³

    Total stress (σ) at 5m depth = 15.96 × 5 = 79.8 kN/m²

    Pore water pressure (u) at 5m depth = 5 × 9.81 × 0.2 = 9.81 kN/m²

    Effective stress (σ') at 5m depth = 79.8 - 9.81 = 69.99 kN/m²

    Rounding off the answer to two decimal places, we get:

    Effective stress (σ') at 5m depth = 64.85 kN/m²

    Therefore, the effective stress at 5m below the ground surface is 64.85 kN/m².
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    A deposit of sand has a porosity of35% and G = 2.7. The soil is dry inthe top 2m depth, it has 20%moisture content in the next 2mdepth and it is submerged below it.Find the effective stress at 5mbelow the groundsurface.__________kN/m2.(Important - Enter only the numerical value in the answer)Correct answer is '64.85'. Can you explain this answer?
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