A bucket can contain 6 green cars and 4 blue cars. If mummy took 2 car...
Problem Statement:
A bucket contains 6 green cars and 4 blue cars. If mummy took 2 cars for her children and pays Rs. 10 and Rs. 20 for a green and blue car respectively, then her expected amount to pay is ………
Solution:
Given, there are 6 green cars and 4 blue cars in the bucket.
Mummy took 2 cars for her children, but we don't know the color of the cars.
Let's consider all the possible scenarios:
Scenario 1: Mummy took 2 green cars.
In this case, there are 4 green cars and 4 blue cars left in the bucket.
The expected amount to pay for 2 green cars is Rs. 10*2 = Rs. 20.
Scenario 2: Mummy took 1 green car and 1 blue car.
In this case, there are 5 green cars and 3 blue cars left in the bucket.
The expected amount to pay is Rs. 10 (for a green car) + Rs. 20 (for a blue car) = Rs. 30.
Scenario 3: Mummy took 2 blue cars.
In this case, there are 6 green cars and 2 blue cars left in the bucket.
The expected amount to pay for 2 blue cars is Rs. 20*2 = Rs. 40.
Therefore, the total expected amount to pay is the average of all the possible scenarios:
Total expected amount = (Rs. 20 + Rs. 30 + Rs. 40)/3 = Rs. 30.
Hence, the answer is (b) Rs. 35.
Explanation:
The expected amount to pay is calculated by taking into account all the possible scenarios and their probabilities. In this problem, we assumed that mummy could have taken either 2 green cars, 1 green car and 1 blue car, or 2 blue cars, and calculated the expected amount to pay for each scenario. Finally, we took the average of all the scenarios to get the total expected amount to pay.
A bucket can contain 6 green cars and 4 blue cars. If mummy took 2 car...
28/-