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The nuclear reaction observed to occur even when very slow moving neutrons (Mn = 1.00874) strike a boron atom at rest. For a particular reaction in which K≈ 0, the helium (MHe = 4.00264) is observed to have a speed of 9.3 x 106 m/sec. Determine the Q - value (MeV) of the reaction { MLi = 7.0160 u)
    Correct answer is '2.82'. Can you explain this answer?
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    The nuclear reactionobserved to occur even when veryslow moving neutro...
    Since the neutron and boron are both initially at rest the total momentum before the reaction is zero and afterward is also zero.
    Therefore MLi VLi = MHe VHe
    We solve this for VLi and substitute it into the equation for kinetic energy. We can use classical kinetic energy with little error, rather than relativistic formulas, be-
    2.82
    Since the neutron and boron are both initially at rest, the total momentum before the reaction is zero and afterward is also zero.
    Therefore MLi VLi = MHe VHe
    We solve this for VLi and substitute it into the equation for kinetic energy. We can use classical kinetic energy with little error, rather than relativistic formulas, because VHe = 9.30 x 106 m/sec is not close to the speed of light c and VLi will be even less Since MLi > MHe. Thus we can write

    We put in numbers, changing the mass in u to kg and recalling that 1.6 x 10-13 J = 1 MeV
     
    Given data Ka = Kx = 0 
    So Q = KLi + KHe

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    The nuclear reactionobserved to occur even when veryslow moving neutro...
    Since the neutron and boron are both initially at rest the total momentum before the reaction is zero and afterward is also zero.
    Therefore MLi VLi = MHe VHe
    We solve this for VLi and substitute it into the equation for kinetic energy. We can use classical kinetic energy with little error, rather than relativistic formulas, be-
    2.82
    Since the neutron and boron are both initially at rest, the total momentum before the reaction is zero and afterward is also zero.
    Therefore MLi VLi = MHe VHe
    We solve this for VLi and substitute it into the equation for kinetic energy. We can use classical kinetic energy with little error, rather than relativistic formulas, because VHe = 9.30 x 106 m/sec is not close to the speed of light c and VLi will be even less Since MLi > MHe. Thus we can write

    We put in numbers, changing the mass in u to kg and recalling that 1.6 x 10-13 J = 1 MeV
     
    Given data Ka = Kx = 0 
    So Q = KLi + KHe

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    The nuclear reactionobserved to occur even when veryslow moving neutrons (Mn = 1.00874) strike a boron atom at rest. For a particular reaction in which Kn≈ 0, the helium (MHe = 4.00264) is observed to have a speed of 9.3 x 106 m/sec. Determine the Q - value (MeV) of the reaction { MLi = 7.0160 u)Correct answer is '2.82'. Can you explain this answer?
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    The nuclear reactionobserved to occur even when veryslow moving neutrons (Mn = 1.00874) strike a boron atom at rest. For a particular reaction in which Kn≈ 0, the helium (MHe = 4.00264) is observed to have a speed of 9.3 x 106 m/sec. Determine the Q - value (MeV) of the reaction { MLi = 7.0160 u)Correct answer is '2.82'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The nuclear reactionobserved to occur even when veryslow moving neutrons (Mn = 1.00874) strike a boron atom at rest. For a particular reaction in which Kn≈ 0, the helium (MHe = 4.00264) is observed to have a speed of 9.3 x 106 m/sec. Determine the Q - value (MeV) of the reaction { MLi = 7.0160 u)Correct answer is '2.82'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The nuclear reactionobserved to occur even when veryslow moving neutrons (Mn = 1.00874) strike a boron atom at rest. For a particular reaction in which Kn≈ 0, the helium (MHe = 4.00264) is observed to have a speed of 9.3 x 106 m/sec. Determine the Q - value (MeV) of the reaction { MLi = 7.0160 u)Correct answer is '2.82'. Can you explain this answer?.
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