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For transistor 2 N 338 the manufacturer specifies Pmax = 100 mW at 250ºC free air temperature and maximum junction temperature of 125ºC. Its thermal resistance isa)10º C/Wb)100º C/Wc)1000º C/Wd)5000º C/WCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about For transistor 2 N 338 the manufacturer specifies Pmax = 100 mW at 250ºC free air temperature and maximum junction temperature of 125ºC. Its thermal resistance isa)10º C/Wb)100º C/Wc)1000º C/Wd)5000º C/WCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For transistor 2 N 338 the manufacturer specifies Pmax = 100 mW at 250ºC free air temperature and maximum junction temperature of 125ºC. Its thermal resistance isa)10º C/Wb)100º C/Wc)1000º C/Wd)5000º C/WCorrect answer is option 'C'. Can you explain this answer?.

Solutions for For transistor 2 N 338 the manufacturer specifies Pmax = 100 mW at 250ºC free air temperature and maximum junction temperature of 125ºC. Its thermal resistance isa)10º C/Wb)100º C/Wc)1000º C/Wd)5000º C/WCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.

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