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If the probability of a horse A winning a race is 1/6 and the probability of a horse B winning the same race is 1/4 , What is the probability that none of them will win
  • a)
    5/12
  • b)
    7/12
  • c)
    1/12
  • d)
    none
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If the probability of a horse A winning a race is 1/6 and the probabil...
Solution:

To find the probability that none of the horses will win, we need to find the probability that both horses will lose.

Let P(A) be the probability of horse A winning and P(B) be the probability of horse B winning.

The probability of both horses losing is given by:

P(¬A ∧ ¬B) = P(¬A) × P(¬B)

where ¬A means "not A" or "A losing" and similarly for ¬B.

Given that P(A) = 1/6 and P(B) = 1/4, we can calculate P(¬A) and P(¬B) as follows:

P(¬A) = 1 - P(A) = 1 - 1/6 = 5/6
P(¬B) = 1 - P(B) = 1 - 1/4 = 3/4

Therefore, the probability of both horses losing is:

P(¬A ∧ ¬B) = P(¬A) × P(¬B) = (5/6) × (3/4) = 15/24 = 5/8

But we need to find the probability that none of the horses will win, which is the same as the probability that both horses will lose. Therefore, the answer is:

P(¬A ∧ ¬B) = 5/8 = 7/12 (option 'B')

Hence, the correct answer is option 'B'.
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Community Answer
If the probability of a horse A winning a race is 1/6 and the probabil...
1-(1/6+1/4)=1-(5/12)=7/12
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