If the probability of a horse A winning a race is 1/6 and the probabil...
Solution:
Given:
Probability of horse A winning the race = 1/6
Probability of horse B winning the race = 1/4
To find:
Probability that one of the horses will win
Formula:
Probability of event A or B = Probability of A + Probability of B - Probability of A and B
P(A or B) = P(A) + P(B) - P(A and B)
Calculation:
Let's calculate the probability of both horses not winning the race first, and then subtract that from 1 to find the probability that one of the horses will win.
Probability of horse A not winning = 1 - 1/6 = 5/6
Probability of horse B not winning = 1 - 1/4 = 3/4
Probability of both horses not winning = Probability of horse A not winning x Probability of horse B not winning
P(A' and B') = (5/6) x (3/4) = 15/24
P(A' and B') = 5/8
Probability of one of the horses winning = 1 - Probability of both horses not winning
P(A or B) = 1 - P(A' and B')
P(A or B) = 1 - 5/8
P(A or B) = 3/8
Answer:
The probability that one of the horses will win is 3/8 or 0.375.