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Consider the CO molecule as a system of two point particles which has both translational and rotational degrees of freedom. Using classical statistical mechanics. the molar specific heat Cv of CO gas is given in form of the Boltzmann constant KB by
  • a)
  • b)
    2KB
  • c)
    3/2 KB
  • d)
    1/2 KB
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Consider the CO molecule as a system of two point particles which has ...
Translation degree of freedom = 3 
Rotational degree of freedom = 2

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Most Upvoted Answer
Consider the CO molecule as a system of two point particles which has ...
Translation degree of freedom = 3 
Rotational degree of freedom = 2

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Consider the CO molecule as a system of two point particles which has both translational and rotational degrees of freedom. Using classical statistical mechanics. the molar specific heat Cv of CO gas is given in form of the Boltzmann constant KB bya)b)2KBc)3/2 KBd)1/2KBCorrect answer is option 'A'. Can you explain this answer?
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Consider the CO molecule as a system of two point particles which has both translational and rotational degrees of freedom. Using classical statistical mechanics. the molar specific heat Cv of CO gas is given in form of the Boltzmann constant KB bya)b)2KBc)3/2 KBd)1/2KBCorrect answer is option 'A'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Consider the CO molecule as a system of two point particles which has both translational and rotational degrees of freedom. Using classical statistical mechanics. the molar specific heat Cv of CO gas is given in form of the Boltzmann constant KB bya)b)2KBc)3/2 KBd)1/2KBCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the CO molecule as a system of two point particles which has both translational and rotational degrees of freedom. Using classical statistical mechanics. the molar specific heat Cv of CO gas is given in form of the Boltzmann constant KB bya)b)2KBc)3/2 KBd)1/2KBCorrect answer is option 'A'. Can you explain this answer?.
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