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Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?
- a)2
- b)3
- c)4
- d)5
Correct answer is option 'B'. Can you explain this answer?
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Let E1 and E2 be two entities in an E/R diagram with simple single-val...
The answer is B, i.e minimum 3 tables. Strong entities E1 and E2 are represented as separate tables. In addition to that many-to-many relationships(R2) must be converted as seperate table by having primary keys of E1 and E2 as foreign keys. One-to-many relaionship (R1) must be transferred to 'many' side table(i.e. E2) by having primary key of one side(E1) as foreign key( this way we need not to make a seperate table for R1). Let relation schema be E1(a1,a2) and E2( b1,b2). Relation E1( a1 is the key)
Relation E2( b1 is the key, a1 is the foreign key, hence R1(one-many) relationship set satisfy here)
Relation R2 ( {a1, b1} combined is the key here , representing many-many relationship R2)
Hence we will have minimum of 3 tables.
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Let E1 and E2 be two entities in an E/R diagram with simple single-val...
Minimum Number of Tables Required to Represent the Situation
To represent the given situation in the relational model, we need to identify the entities, relationships, and their cardinality. Based on that, we can determine the minimum number of tables required.
Entities and Relationships
- Entities: E1 and E2
- Relationships: R1 (one-to-many between E1 and E2) and R2 (many-to-many between E1 and E2)
Cardinality
- R1: One E1 entity can have many E2 entities, but each E2 entity can only belong to one E1 entity. This is a one-to-many relationship.
- R2: Each E1 entity can be related to many E2 entities, and each E2 entity can be related to many E1 entities. This is a many-to-many relationship.
Minimum Number of Tables
To represent the given situation in the relational model, we need at least three tables:
- Table for E1 entity: This table will have a primary key for E1 and attributes for its simple single-valued attributes.
- Table for E2 entity: This table will have a primary key for E2 and attributes for its simple single-valued attributes.
- Table for R2 relationship: This table will have foreign keys for both E1 and E2 entities to represent the many-to-many relationship. This table will act as a junction table.
However, we also need to represent the one-to-many relationship between E1 and E2. To do that, we can either add a foreign key for E1 in the E2 table or create a separate table for the R1 relationship. So, the minimum number of tables required is three or four.
Therefore, the correct answer is option B (three tables).
To represent the given situation in the relational model, we need to identify the entities, relationships, and their cardinality. Based on that, we can determine the minimum number of tables required.
Entities and Relationships
- Entities: E1 and E2
- Relationships: R1 (one-to-many between E1 and E2) and R2 (many-to-many between E1 and E2)
Cardinality
- R1: One E1 entity can have many E2 entities, but each E2 entity can only belong to one E1 entity. This is a one-to-many relationship.
- R2: Each E1 entity can be related to many E2 entities, and each E2 entity can be related to many E1 entities. This is a many-to-many relationship.
Minimum Number of Tables
To represent the given situation in the relational model, we need at least three tables:
- Table for E1 entity: This table will have a primary key for E1 and attributes for its simple single-valued attributes.
- Table for E2 entity: This table will have a primary key for E2 and attributes for its simple single-valued attributes.
- Table for R2 relationship: This table will have foreign keys for both E1 and E2 entities to represent the many-to-many relationship. This table will act as a junction table.
However, we also need to represent the one-to-many relationship between E1 and E2. To do that, we can either add a foreign key for E1 in the E2 table or create a separate table for the R1 relationship. So, the minimum number of tables required is three or four.
Therefore, the correct answer is option B (three tables).
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Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?
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Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?.
Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let E1 and E2 be two entities in an E/R diagram with simple single-valued attributes. R1 and R2 are two relationships between E1 and E2, where R1 is one-to-many and R2 is many-to-many. R1 and R2 do not have any attributes of their own. What is the minimum number of tables required to represent this situation in the relational model?a)2b)3c)4d)5Correct answer is option 'B'. Can you explain this answer?.
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