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F(ABC) = (A + B + AB) (A + C + AC) has simplified expression
- a)A + B + C
- b)ABC
- c)A + BC
- d)B + A C
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
F(ABC) = (A + B + AB) (A + C + AC) has simplified expressiona)A + B + ...
F(A, BC) = [A + B(1 +A)] [A +C (1+A)]
= (A+B) (A+C) = A + AB + BC + AC
= A(A+B) + BC+AC
= A + AC + BC
= A(1+C) + AC
= A + BC
= (A+B) (A+C) = A + AB + BC + AC
= A(A+B) + BC+AC
= A + AC + BC
= A(1+C) + AC
= A + BC
Most Upvoted Answer
F(ABC) = (A + B + AB) (A + C + AC) has simplified expressiona)A + B + ...
F(A, BC) = [A + B(1 +A)] [A +C (1+A)]
= (A+B) (A+C) = A + AB + BC + AC
= A(A+B) + BC+AC
= A + AC + BC
= A(1+C) + AC
= A + BC
= (A+B) (A+C) = A + AB + BC + AC
= A(A+B) + BC+AC
= A + AC + BC
= A(1+C) + AC
= A + BC
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Community Answer
F(ABC) = (A + B + AB) (A + C + AC) has simplified expressiona)A + B + ...
It could be both option c and d.
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F(ABC) = (A + B + AB) (A + C + AC) has simplified expressiona)A + B + Cb)ABCc)A + BCd)B + A CCorrect answer is option 'C'. Can you explain this answer?
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