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If phase angle of open loop transfer function becomes - 180º at frequency ω1, then gain margin is equal to
  • a)
    |G(jω1)|
  • b)
  • c)
    1 + |G(jω1)|
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If phase angle of open loop transfer function becomes - 180º at f...
If gain is a, gain margin is . In this case gain is |G(jω1)|.
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If phase angle of open loop transfer function becomes - 180º at frequency ω1, then gain margin is equal toa)|G(jω1)|b)c)1 + |G(jω1)|d)Correct answer is option 'B'. Can you explain this answer?
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