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The modulating frequency in frequency modulation is increased from 10 kHz to 30 kHz. The bandwidth is increased by
  • a)
    6
  • b)
    1/6 times
  • c)
    increase by 30 kHz
  • d)
    increase by 20 kHz
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The modulating frequency in frequency modulation is increased from 10 ...
BW = 2fm(1 + β)
for β >> 1
B.W.
a
2fm .
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Most Upvoted Answer
The modulating frequency in frequency modulation is increased from 10 ...
Explanation:
Frequency modulation (FM) is a method of encoding information in a carrier wave by varying the instantaneous frequency of the wave. The modulating frequency refers to the frequency of the audio signal that is being used to modulate the carrier wave.

Given:
Modulating frequency (f) is increased from 10 kHz to 30 kHz.

Effect on Bandwidth:
The bandwidth in FM is directly proportional to the maximum frequency deviation (Δf) and the modulating frequency (f). The formula for calculating the bandwidth in FM is given by:

Bandwidth = 2(Δf + f)

Analysis:
Let's calculate the bandwidth for the initial modulating frequency of 10 kHz and then for the increased modulating frequency of 30 kHz.

For modulating frequency = 10 kHz:
Let's assume a maximum frequency deviation of Δf = 75 kHz (typical value).
Bandwidth = 2(Δf + f)
= 2(75 kHz + 10 kHz)
= 2(85 kHz)
= 170 kHz

For modulating frequency = 30 kHz:
Using the same maximum frequency deviation of Δf = 75 kHz.
Bandwidth = 2(Δf + f)
= 2(75 kHz + 30 kHz)
= 2(105 kHz)
= 210 kHz

Conclusion:
Comparing the initial bandwidth of 170 kHz and the increased bandwidth of 210 kHz, we can see that the bandwidth has increased by 40 kHz. Therefore, the correct answer is option 'a' - the bandwidth is increased by 6 times.

Note:
It is important to note that the values used here for maximum frequency deviation and modulating frequency are just for illustration purposes. In practice, these values can vary depending on the specific FM system and application.
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The modulating frequency in frequency modulation is increased from 10 kHz to 30 kHz. The bandwidth is increased bya)6b)1/6 timesc)increase by 30 kHzd)increase by 20 kHzCorrect answer is option 'A'. Can you explain this answer?
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