A p-n junction diode in series with a 100 ohms resistor is forward bia...
Reverse current at t = 0 when the voltage
is instantaneously reversed to - V
R = - 10 V is
Negative sign indicating reversal of current and voltage.
∴
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A p-n junction diode in series with a 100 ohms resistor is forward bia...
Analysis:
To determine the reverse current that flows through the diode at t = 0, we need to consider the behavior of the diode in both the forward and reverse biased conditions.
Forward Bias:
When the p-n junction diode is forward biased, the positive terminal of the voltage source is connected to the p-side of the diode, and the negative terminal is connected to the n-side. This causes the diode to conduct current.
Given:
- Forward current (I) = 100 mA
- Resistance (R) = 100 Ω
Using Ohm's Law, we can determine the voltage (V) across the resistor:
V = I * R
V = 100 mA * 100 Ω
V = 10 V
Therefore, when the diode is forward biased, the voltage across the combination is 10 V.
Reverse Bias:
When the voltage across the combination is instantaneously reversed to 10 V at t = 0, the positive terminal of the voltage source is now connected to the n-side of the diode, and the negative terminal is connected to the p-side. This causes the diode to be reverse biased.
In reverse bias, the diode does not conduct current unless the reverse voltage exceeds the diode's breakdown voltage. However, we can assume that the reverse voltage of 10 V is below the breakdown voltage of the diode.
Answer:
The reverse current that flows through the diode at t = 0 is approximately 100 mA.