At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise in temperature due to (1992 - 1 Mark)a)Increase in average molecular speedb)Increased rate of collisions amongst moleculesc)Increase in molecular attractiond)Decrease in mean free pathCorrect answer is option 'A'. Can you explain this answer?

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At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise in temperature due to (1992 - 1 Mark)

a)
Increase in average molecular speed
b)
Increased rate of collisions amongst molecules
c)
Increase in molecular attraction
d)
Decrease in mean free path

Correct answer is option 'A'. Can you explain this answer?

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At constant volume, for a fixed number of moles of a gas the pressure ...

Due to increase in the temperature, the kinetic energy of the gas molecules increases resulting in an increase in average molecular speed. The molecules are bombarded to the walls of the container with a greater velocity resulting in an increase in pressure.

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For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.A sample of mixture of A(g), B(g) and C(g) under equilibrium has a mean molecular weight (observe d) is 80.The equilibrium is Find the degree of dissociation for A(g).

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For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.The K for the reaction is 640 mm at 775 K. The percentage dissociation of N2O4 at equilibrium pressure of 160 mm is

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At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise in temperature due to (1992 - 1 Mark)a)Increase in average molecular speedb)Increased rate of collisions amongst moleculesc)Increase in molecular attractiond)Decrease in mean free pathCorrect answer is option 'A'. Can you explain this answer?

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At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise in temperature due to (1992 - 1 Mark)a)Increase in average molecular speedb)Increased rate of collisions amongst moleculesc)Increase in molecular attractiond)Decrease in mean free pathCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise in temperature due to (1992 - 1 Mark)a)Increase in average molecular speedb)Increased rate of collisions amongst moleculesc)Increase in molecular attractiond)Decrease in mean free pathCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At constant volume, for a fixed number of moles of a gas the pressure of the gas increases with rise in temperature due to (1992 - 1 Mark)a)Increase in average molecular speedb)Increased rate of collisions amongst moleculesc)Increase in molecular attractiond)Decrease in mean free pathCorrect answer is option 'A'. Can you explain this answer?.

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