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Assume every process requires 3 seconds of service time in a system with single processor. If new processes are arriving at the rate of 10 processes per minute, then estimate the fraction of time CPU is busy in system?
- a)20%
- b)30%
- c)50%
- d)60%
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Assume every process requires 3 seconds of service time in a system wi...
10 processes -> 1 min
1 process-> 1/10 min = 6 sec (Arrival rate)
Each process -> 3 sec service time 3/6 * 100 = 50% of time CPU is busy.
1 process-> 1/10 min = 6 sec (Arrival rate)
Each process -> 3 sec service time 3/6 * 100 = 50% of time CPU is busy.
Most Upvoted Answer
Assume every process requires 3 seconds of service time in a system wi...
To estimate the fraction of time the CPU is busy in the system, we need to consider the service time of each process and the arrival rate of new processes.
Service Time of Each Process:
Given that each process requires 3 seconds of service time, we can calculate the average time taken to serve one process as follows:
Average Service Time = 3 seconds
Arrival Rate of New Processes:
The problem states that new processes are arriving at the rate of 10 processes per minute. To calculate the arrival rate per second, we divide the arrival rate per minute by 60 (since there are 60 seconds in a minute):
Arrival Rate = 10 processes / 60 seconds
= 1/6 processes per second
Fraction of Time CPU is Busy:
To estimate the fraction of time the CPU is busy, we need to consider the time it takes to serve one process and the time between arrivals of new processes.
Let's assume the system operates for a duration of 1 minute (60 seconds) to align with the arrival rate. Within this minute, the CPU can serve a maximum of 20 processes (60 seconds / 3 seconds per process).
The total time required to serve these 20 processes is:
Total Service Time = 20 processes * 3 seconds per process
= 60 seconds
As the CPU can serve these 20 processes in 60 seconds, and the arrival rate is 1/6 processes per second, the CPU will be idle for the remaining time. The idle time is calculated as:
Idle Time = Total Time - Total Service Time
= 60 seconds - 60 seconds
= 0 seconds
Therefore, the fraction of time the CPU is busy is:
Fraction of Time CPU is Busy = Total Service Time / Total Time * 100%
= 60 seconds / 60 seconds * 100%
= 100%
Hence, the correct option is c) 50%.
Service Time of Each Process:
Given that each process requires 3 seconds of service time, we can calculate the average time taken to serve one process as follows:
Average Service Time = 3 seconds
Arrival Rate of New Processes:
The problem states that new processes are arriving at the rate of 10 processes per minute. To calculate the arrival rate per second, we divide the arrival rate per minute by 60 (since there are 60 seconds in a minute):
Arrival Rate = 10 processes / 60 seconds
= 1/6 processes per second
Fraction of Time CPU is Busy:
To estimate the fraction of time the CPU is busy, we need to consider the time it takes to serve one process and the time between arrivals of new processes.
Let's assume the system operates for a duration of 1 minute (60 seconds) to align with the arrival rate. Within this minute, the CPU can serve a maximum of 20 processes (60 seconds / 3 seconds per process).
The total time required to serve these 20 processes is:
Total Service Time = 20 processes * 3 seconds per process
= 60 seconds
As the CPU can serve these 20 processes in 60 seconds, and the arrival rate is 1/6 processes per second, the CPU will be idle for the remaining time. The idle time is calculated as:
Idle Time = Total Time - Total Service Time
= 60 seconds - 60 seconds
= 0 seconds
Therefore, the fraction of time the CPU is busy is:
Fraction of Time CPU is Busy = Total Service Time / Total Time * 100%
= 60 seconds / 60 seconds * 100%
= 100%
Hence, the correct option is c) 50%.
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Assume every process requires 3 seconds of service time in a system with single processor. If new processes are arriving at the rate of 10 processes per minute, then estimate the fraction of time CPU is busy in system?a)20%b)30%c)50%d)60%Correct answer is option 'C'. Can you explain this answer?
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