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Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
  • a)
    9
  • b)
    11
  • c)
    13
  • d)
    15
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Three times the first of three consecutive odd integers is 3 more than...
Let the three integers be: xx + 2 and x + 4.
Then, 3x = 2(x + 4) + 3
► x = 11.
Third integer = x + 4 = 15.
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Most Upvoted Answer
Three times the first of three consecutive odd integers is 3 more than...
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3
x = 11.
Third integer = x + 4 = 15.
Free Test
Community Answer
Three times the first of three consecutive odd integers is 3 more than...
**Problem Analysis:**
Let's assume the first odd integer to be x. According to the given information:
Three times the first integer = 3x
Twice the third integer = 2(x + 4) [Since the integers are consecutive, the third integer will be x + 4]

**Solution:**
According to the given information:
3x = 2(x + 4) + 3

**Step 1:**
Simplify the expression.
3x = 2x + 8 + 3
3x = 2x + 11

**Step 2:**
Subtract 2x from both sides of the equation to isolate x.
3x - 2x = 2x + 11 - 2x
x = 11

**Step 3:**
The third integer can be calculated by adding 4 to the first integer.
Third Integer = x + 4 = 11 + 4 = 15

Therefore, the third integer is 15.

**Conclusion:**
Thus, option D (15) is the correct answer.
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Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:a)9b)11c)13d)15Correct answer is option 'D'. Can you explain this answer?
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