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x² – 26x + 168 = 0
y² – 34y + 285 = 0
- a)X > Y
- b)X < Y
- c)X ≥ Y
- d)X ≤ Y
- e)X = Y or relation cannot be established
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
x² – 26x + 168 = 0y² – 34y + 285 = 0a)X > Yb)...
x² – 26x + 168 = 0
x = 12, 14
y² – 34y + 285 = 0
y = 15, 19
x = 12, 14
y² – 34y + 285 = 0
y = 15, 19
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Community Answer
x² – 26x + 168 = 0y² – 34y + 285 = 0a)X > Yb)...
Understanding the Quadratic Equations
To compare the values of X and Y from the given quadratic equations, we first need to solve each equation.
Equation for X
The first equation is:
x² - 26x + 168 = 0
We can use the quadratic formula:
x = [26 ± √(26² - 4 × 1 × 168)] / (2 × 1)
Calculating the discriminant:
- 26² = 676
- 4 × 1 × 168 = 672
- Discriminant = 676 - 672 = 4
Now we can find the roots:
- x = [26 ± √4] / 2
- x = [26 ± 2] / 2
This gives us two roots:
- x₁ = (28 / 2) = 14
- x₂ = (24 / 2) = 12
Thus, X can take the values 12 or 14.
Equation for Y
The second equation is:
y² - 34y + 285 = 0
Using the quadratic formula:
y = [34 ± √(34² - 4 × 1 × 285)] / (2 × 1)
Calculating the discriminant:
- 34² = 1156
- 4 × 1 × 285 = 1140
- Discriminant = 1156 - 1140 = 16
Finding the roots:
- y = [34 ± √16] / 2
- y = [34 ± 4] / 2
This gives us two roots:
- y₁ = (38 / 2) = 19
- y₂ = (30 / 2) = 15
Thus, Y can take the values 15 or 19.
Comparison of X and Y
Now we compare the values of X and Y:
- Maximum value of X = 14
- Minimum value of Y = 15
Since 14 < 15,="" we="" find="" that="" x="" />< />
Conclusion
Therefore, the correct answer is option 'B': X < y.="" />
To compare the values of X and Y from the given quadratic equations, we first need to solve each equation.
Equation for X
The first equation is:
x² - 26x + 168 = 0
We can use the quadratic formula:
x = [26 ± √(26² - 4 × 1 × 168)] / (2 × 1)
Calculating the discriminant:
- 26² = 676
- 4 × 1 × 168 = 672
- Discriminant = 676 - 672 = 4
Now we can find the roots:
- x = [26 ± √4] / 2
- x = [26 ± 2] / 2
This gives us two roots:
- x₁ = (28 / 2) = 14
- x₂ = (24 / 2) = 12
Thus, X can take the values 12 or 14.
Equation for Y
The second equation is:
y² - 34y + 285 = 0
Using the quadratic formula:
y = [34 ± √(34² - 4 × 1 × 285)] / (2 × 1)
Calculating the discriminant:
- 34² = 1156
- 4 × 1 × 285 = 1140
- Discriminant = 1156 - 1140 = 16
Finding the roots:
- y = [34 ± √16] / 2
- y = [34 ± 4] / 2
This gives us two roots:
- y₁ = (38 / 2) = 19
- y₂ = (30 / 2) = 15
Thus, Y can take the values 15 or 19.
Comparison of X and Y
Now we compare the values of X and Y:
- Maximum value of X = 14
- Minimum value of Y = 15
Since 14 < 15,="" we="" find="" that="" x="" />< />
Conclusion
Therefore, the correct answer is option 'B': X < y.="" />
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x² – 26x + 168 = 0y² – 34y + 285 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer? for Quant 2026 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about x² – 26x + 168 = 0y² – 34y + 285 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for x² – 26x + 168 = 0y² – 34y + 285 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer?.
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