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The cyanide ion , CN and N2 are isoelectron ic. But in contrast to CN, N2 is chemically inert, because of (1992 - 1 Mark)
  • a)
    low bond energy
  • b)
    absence of bond polarity
  • c)
    unsymmetrical electron distribution
  • d)
    presence of more number of electrons in bonding orbitals
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The cyanide ion , CN– and N2 are isoelectron ic. But in contrast...
Correct option is B ie absence of bond polarity other reason can be that since they are attached by triple bond it requires a high amount of energy to break the bond.
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The cyanide ion , CN– and N2 are isoelectron ic. But in contrast to CN–, N2 is chemically inert, because of (1992 - 1 Mark)a)low bond energyb)absence of bond polarityc)unsymmetrical electron distributiond)presence of more number of electrons in bonding orbitalsCorrect answer is option 'B'. Can you explain this answer?
Question Description
The cyanide ion , CN– and N2 are isoelectron ic. But in contrast to CN–, N2 is chemically inert, because of (1992 - 1 Mark)a)low bond energyb)absence of bond polarityc)unsymmetrical electron distributiond)presence of more number of electrons in bonding orbitalsCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The cyanide ion , CN– and N2 are isoelectron ic. But in contrast to CN–, N2 is chemically inert, because of (1992 - 1 Mark)a)low bond energyb)absence of bond polarityc)unsymmetrical electron distributiond)presence of more number of electrons in bonding orbitalsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The cyanide ion , CN– and N2 are isoelectron ic. But in contrast to CN–, N2 is chemically inert, because of (1992 - 1 Mark)a)low bond energyb)absence of bond polarityc)unsymmetrical electron distributiond)presence of more number of electrons in bonding orbitalsCorrect answer is option 'B'. Can you explain this answer?.
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