The transfer function of a system is G(s) = 100/(s+1) (s+100). For a u...
Answer: b
Explanation: Comparing the equation with the characteristic equation and then finding the value of G and w and calculating the value of settling time as 4 sec from 4/Gw.
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The transfer function of a system is G(s) = 100/(s+1) (s+100). For a u...
Transfer Function:
The given transfer function of the system is G(s) = 100/(s+1)(s+100).
Step Response:
To find the settling time for a unit step input, we need to analyze the step response of the system. The step response is the output of the system when a unit step input is applied.
Settling Time:
The settling time is defined as the time it takes for the system output to reach and stay within a certain percentage (usually 2%) of the final value.
2% Criterion:
In this case, the 2% criterion means that the output must reach and stay within 2% of the final value.
Calculation:
To find the settling time, we need to calculate the time it takes for the output to reach and stay within 2% of the final value.
Step 1:
Convert the transfer function to its time-domain representation. We can use partial fraction expansion to do this.
G(s) = 100/[(s+1)(s+100)] = A/(s+1) + B/(s+100)
Multiply both sides by (s+1)(s+100) to get rid of the denominators.
100 = A(s+100) + B(s+1)
Step 2:
Now, we can equate the coefficients of the powers of s on both sides of the equation.
For s^0 term: 100 = 100A + B
For s^1 term: 0 = 100A + A + 100B
Solving these equations, we get A = 1/99 and B = -1/99.
Step 3:
Now, we can write the time-domain representation of the transfer function.
G(s) = (1/99)/(s+1) - (1/99)/(s+100)
Step 4:
To calculate the settling time, we can find the time it takes for the output to reach and stay within 2% of the final value.
Let's assume the final value is 1 (since it's a unit step input).
2% of 1 is 0.02.
So, we need to find the time it takes for the output to reach and stay within 0.02 of 1.
Step 5:
We can use the inverse Laplace transform to find the time-domain representation of the transfer function.
Taking the inverse Laplace transform of G(s), we get g(t) = (1/99)e^(-t) - (1/99)e^(-100t).
Step 6:
Now, we need to find the time it takes for the output to reach and stay within 0.02 of 1.
Setting g(t) = 1 - 0.02 = 0.98, we can solve for t.
0.98 = (1/99)e^(-t) - (1/99)e^(-100t)
Solving this equation, we get t ≈ 4 seconds.
Therefore, the approximate settling time for a unit step input with a 2% criterion is 4 seconds.