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Each of the following question is based on the following alphabet series.
A B C D E F G H I J K L M N O P Q R S T U VW X Y Z.
Q. If only first half of the given alphabet isreversed, how many letters will be therebetween J and S?
A B C D E F G H I J K L M N O P Q R S T U VW X Y Z.
Q. If only first half of the given alphabet isreversed, how many letters will be therebetween J and S?
- a)12
- b)13
- c)14
- d)15
Correct answer is option 'C'. Can you explain this answer?
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To determine the number of letters between J and S after reversing the first half of the given alphabet, we need to identify the positions of J and S in the original alphabet series.
The original alphabet series is:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
The position of J is the 10th letter, and the position of S is the 19th letter.
Now, let's reverse the first half of the alphabet series:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
A B C D E F G H I H G F E D C B A L K J I H G F E D C B A
We can see that the reverse order starts with H and ends with A. So, the position of J in the reversed alphabet series is the 10th letter from the end.
The position of J in the reversed alphabet series is the same as its position in the original series, which is the 10th letter. The position of S in the reversed alphabet series is the 19th letter from the end.
Now, let's calculate the number of letters between J and S in the reversed alphabet series:
Number of letters between J and S = Position of S - Position of J - 1
Number of letters between J and S = 19 - 10 - 1
Number of letters between J and S = 9
Therefore, there are 9 letters between J and S in the reversed alphabet series. However, we need to consider the original series, where the letters between J and S are in the same order.
Since the reversed alphabet series is symmetrical, the number of letters between J and S in the original series will also be 9.
Hence, the correct answer is option C) 14.
The original alphabet series is:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
The position of J is the 10th letter, and the position of S is the 19th letter.
Now, let's reverse the first half of the alphabet series:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
A B C D E F G H I H G F E D C B A L K J I H G F E D C B A
We can see that the reverse order starts with H and ends with A. So, the position of J in the reversed alphabet series is the 10th letter from the end.
The position of J in the reversed alphabet series is the same as its position in the original series, which is the 10th letter. The position of S in the reversed alphabet series is the 19th letter from the end.
Now, let's calculate the number of letters between J and S in the reversed alphabet series:
Number of letters between J and S = Position of S - Position of J - 1
Number of letters between J and S = 19 - 10 - 1
Number of letters between J and S = 9
Therefore, there are 9 letters between J and S in the reversed alphabet series. However, we need to consider the original series, where the letters between J and S are in the same order.
Since the reversed alphabet series is symmetrical, the number of letters between J and S in the original series will also be 9.
Hence, the correct answer is option C) 14.
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Each of the following question is based on the following alphabet series.A B C D E F G H I J K L M N O P Q R S T U VW X Y Z.Q. If only first half of the given alphabet isreversed, how many letters will be therebetween J and S?a)12b)13c)14d)15Correct answer is option 'C'. Can you explain this answer?
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