If ZOO stands for 56, DEER stands for 32then for which numerical value...
Z = 26; O = 15.
ZOO = 26 + 15 + 15 = 56.
D = 4, E = 5; R = 18.
DEER = 4 + 5 + 5 + 18 = 32.
LION = 12 + 9 + 15 + 14 = 50
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If ZOO stands for 56, DEER stands for 32then for which numerical value...
Given, ZOO = 56 and DEER = 32.
We need to find the numerical value for LION.
To solve this problem, we need to look for a pattern in the given values.
Observations:
- The word ZOO has three letters and its value is 56, which is a multiple of 8 (i.e. 8 x 7)
- The word DEER has four letters and its value is 32, which is a multiple of 8 (i.e. 8 x 4)
Based on these observations, we can assume that the numerical value for a word is calculated by multiplying the number of letters in the word with 8.
Using this assumption, we can calculate the value for LION:
- LION has four letters, so its value would be 4 x 8 = 32
However, this answer contradicts with the given answer options. Therefore, we need to look for another pattern.
Another observation:
- If we add the numerical values of the letters in each word, we get the given values.
Using this pattern, we can find the numerical value for LION:
- LION = L + I + O + N
- L = 12, I = 9, O = 15, N = 14 (based on their positions in the English alphabet)
- LION = 12 + 9 + 15 + 14 = 50
Hence, the numerical value for LION is 50. Therefore, option C is the correct answer.
If ZOO stands for 56, DEER stands for 32then for which numerical value...
Option c because z comes last so it's value equals to 26 o comes fifteenth SO it's value equals to 15 and there are 2 o =26+15+15=56 D comes fourth and E comes fifth and R comes Eighteenth =4+5+5+18=32 now comes lion L comes 12th I comes 9th O comes 15 th and N comes 14th=12+9+15+14=50 and so option c is correct
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