If ZOO stands for 56, DEER stands for 32 then for which numerical valu...
Z = 26; O = 15.
ZOO = 26 + 15 + 15 = 56.
D = 4, E = 5; R = 18.
DEER = 4 + 5 + 5 + 18 = 32.
LION = 12 + 9 + 15 + 14 = 50
View all questions of this test
If ZOO stands for 56, DEER stands for 32 then for which numerical valu...
Given, ZOO = 56 and DEER = 32.
We need to find the numerical value for LION.
Approach:
We can observe that the numerical value for each letter is obtained by multiplying the position of the letter in the English alphabet by 2.
For example,
- A = 1, B = 2, C = 3, ... , Z = 26
- Z = 26, its position in the alphabet is 26, so its numerical value is 26*2 = 52
Using this logic, we can find the numerical value for L, I, O, and N and add them up to get the value for LION.
Calculation:
- L = 12, its position in the alphabet is 12, so its numerical value is 12*2 = 24
- I = 9, its position in the alphabet is 9, so its numerical value is 9*2 = 18
- O = 15, its position in the alphabet is 15, so its numerical value is 15*2 = 30
- N = 14, its position in the alphabet is 14, so its numerical value is 14*2 = 28
Therefore, the numerical value for LION = 24 + 18 + 30 + 28 = 100.
Hence, the correct option is (C) 50.
If ZOO stands for 56, DEER stands for 32 then for which numerical valu...
Z=26,o=15,o=15
zoo=26+15+15=56
d=4,e=5,e=5,r=18
deer=4+5+5+18=32
l=12,i=9,o=15,n=14
lion=12+9+15+14=50
To make sure you are not studying endlessly, EduRev has designed Class 8 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 8.