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The cut off frequency of a TE wave with waveguide dimension of a= 3.5 cm in a medium of permittivity 2.2 is
  • a)
    2.88 GHz
  • b)
    3.32 GHz
  • c)
    4.5 GHz
  • d)
    2.12 GHz
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The cut off frequency of a TE wave with waveguide dimension of a= 3.5 ...
Answer: a
Explanation: The cut off frequency of a TE wave in any other medium is mc/2a√εr. On substituting for a = 0.035 and εr = 2.2, we get the cut off frequency as 2.88 GHz.
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Most Upvoted Answer
The cut off frequency of a TE wave with waveguide dimension of a= 3.5 ...
Given:
Waveguide dimension, a = 3.5 cm
Permittivity of medium, ε = 2.2

To find:
Cut-off frequency of the TE wave

Solution:
The cut-off frequency of a TE (Transverse Electric) wave in a rectangular waveguide can be determined using the following formula:

fc = (c / 2a) * √(2 / ε)

Where:
fc is the cut-off frequency
c is the speed of light in vacuum (approximately 3 × 10^8 m/s)
a is the width of the waveguide
ε is the permittivity of the medium

Substituting the given values:
a = 3.5 cm = 0.035 m
ε = 2.2
c = 3 × 10^8 m/s

Calculating the cut-off frequency:
fc = (3 × 10^8 / 2 × 0.035) * √(2 / 2.2)
= (8.57 × 10^9) * √(1.0)
= 8.57 × 10^9 Hz
= 8.57 GHz

Answer:
Therefore, the cut-off frequency of the TE wave with a waveguide dimension of a = 3.5 cm in a medium of permittivity ε = 2.2 is 8.57 GHz, which is not one of the given options. Therefore, none of the provided options (A, B, C, D) is correct.
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The cut off frequency of a TE wave with waveguide dimension of a= 3.5 cm in a medium of permittivity 2.2 isa)2.88 GHzb)3.32 GHzc)4.5 GHzd)2.12 GHzCorrect answer is option 'A'. Can you explain this answer?
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