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In a radioactive labelling based tracer technique carbon 1 of glucose was labelled and products were evaluated, which of the following statements are true.
- a)Only 50% of the pyruvate molecules will have radioactivity
- b)All the pyruvate molecules will be labelled
- c)Carbon dioxide released during the formation of acetyl CoA will be radiolabelled.
- d)Radioactivity will also be observed in the acetyl coA
Correct answer is option 'A,D'. Can you explain this answer?
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In a radioactive labelling based tracer technique carbon 1 of glucose ...
Carbon 1 or the glucose is retained in 50% of the pyruvate molecules. While C3 and C4 make carbon dioxide. Therefore only 50% of the pyruvate will have radioactivity and it will also be observed in acetyl CoA, but not in carbon dioxide.
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In a radioactive labelling based tracer technique carbon 1 of glucose ...
Answer:
Introduction:
In a radioactive labelling based tracer technique, a specific carbon atom in a molecule is replaced with a radioactive isotope. This allows tracking the movement of the labelled molecule within a biological system.
Statement a:
Only 50% of the pyruvate molecules will have radioactivity.
Explanation:
- Glucose is a 6-carbon molecule, and carbon 1 of glucose is labelled with a radioactive isotope.
- During the process of glucose metabolism, glucose is converted into pyruvate through the process of glycolysis.
- Since carbon 1 of glucose is labelled, only half of the pyruvate molecules formed will have radioactivity.
- This is because glucose is split into two 3-carbon molecules (pyruvate) during glycolysis, and only one of them will contain the labelled carbon atom.
Statement b:
All the pyruvate molecules will be labelled.
Explanation:
- This statement is incorrect because only one of the two pyruvate molecules formed during glycolysis will contain the labelled carbon atom.
- The other pyruvate molecule will not have radioactivity.
Statement c:
Carbon dioxide released during the formation of acetyl CoA will be radiolabelled.
Explanation:
- When pyruvate is converted into acetyl CoA in the mitochondria, carbon dioxide is released as a byproduct.
- Since carbon 1 of glucose is labelled, the carbon dioxide released during the formation of acetyl CoA will not be radiolabelled.
- The radiolabelled carbon atom remains in the acetyl CoA molecule.
Statement d:
Radioactivity will also be observed in the acetyl CoA.
Explanation:
- This statement is true because the labelled carbon atom from glucose remains in the acetyl CoA molecule.
- Therefore, acetyl CoA will contain the radiolabelled carbon atom.
- This allows tracking the movement of the labelled carbon atom throughout the citric acid cycle and subsequent metabolic pathways.
Conclusion:
Based on the explanations provided, the correct statements are:
- Only 50% of the pyruvate molecules will have radioactivity (Statement a)
- Radioactivity will also be observed in the acetyl CoA (Statement d)
Introduction:
In a radioactive labelling based tracer technique, a specific carbon atom in a molecule is replaced with a radioactive isotope. This allows tracking the movement of the labelled molecule within a biological system.
Statement a:
Only 50% of the pyruvate molecules will have radioactivity.
Explanation:
- Glucose is a 6-carbon molecule, and carbon 1 of glucose is labelled with a radioactive isotope.
- During the process of glucose metabolism, glucose is converted into pyruvate through the process of glycolysis.
- Since carbon 1 of glucose is labelled, only half of the pyruvate molecules formed will have radioactivity.
- This is because glucose is split into two 3-carbon molecules (pyruvate) during glycolysis, and only one of them will contain the labelled carbon atom.
Statement b:
All the pyruvate molecules will be labelled.
Explanation:
- This statement is incorrect because only one of the two pyruvate molecules formed during glycolysis will contain the labelled carbon atom.
- The other pyruvate molecule will not have radioactivity.
Statement c:
Carbon dioxide released during the formation of acetyl CoA will be radiolabelled.
Explanation:
- When pyruvate is converted into acetyl CoA in the mitochondria, carbon dioxide is released as a byproduct.
- Since carbon 1 of glucose is labelled, the carbon dioxide released during the formation of acetyl CoA will not be radiolabelled.
- The radiolabelled carbon atom remains in the acetyl CoA molecule.
Statement d:
Radioactivity will also be observed in the acetyl CoA.
Explanation:
- This statement is true because the labelled carbon atom from glucose remains in the acetyl CoA molecule.
- Therefore, acetyl CoA will contain the radiolabelled carbon atom.
- This allows tracking the movement of the labelled carbon atom throughout the citric acid cycle and subsequent metabolic pathways.
Conclusion:
Based on the explanations provided, the correct statements are:
- Only 50% of the pyruvate molecules will have radioactivity (Statement a)
- Radioactivity will also be observed in the acetyl CoA (Statement d)
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In a radioactive labelling based tracer technique carbon 1 of glucose was labelled and products were evaluated, which of the following statements are true.a)Only 50% of the pyruvate molecules will have radioactivityb)All the pyruvate molecules will be labelledc)Carbon dioxide released during the formation of acetyl CoA will be radiolabelled.d)Radioactivity will also be observed in the acetyl coACorrect answer is option 'A,D'. Can you explain this answer?
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In a radioactive labelling based tracer technique carbon 1 of glucose was labelled and products were evaluated, which of the following statements are true.a)Only 50% of the pyruvate molecules will have radioactivityb)All the pyruvate molecules will be labelledc)Carbon dioxide released during the formation of acetyl CoA will be radiolabelled.d)Radioactivity will also be observed in the acetyl coACorrect answer is option 'A,D'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In a radioactive labelling based tracer technique carbon 1 of glucose was labelled and products were evaluated, which of the following statements are true.a)Only 50% of the pyruvate molecules will have radioactivityb)All the pyruvate molecules will be labelledc)Carbon dioxide released during the formation of acetyl CoA will be radiolabelled.d)Radioactivity will also be observed in the acetyl coACorrect answer is option 'A,D'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a radioactive labelling based tracer technique carbon 1 of glucose was labelled and products were evaluated, which of the following statements are true.a)Only 50% of the pyruvate molecules will have radioactivityb)All the pyruvate molecules will be labelledc)Carbon dioxide released during the formation of acetyl CoA will be radiolabelled.d)Radioactivity will also be observed in the acetyl coACorrect answer is option 'A,D'. Can you explain this answer?.
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