Class 9 Exam > Class 9 Questions > In the given circle, O is the centre and∠...
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In the given circle, O is the centre and ∠BDC = 42o. Then, ∠ACB is equal to
- a)58o
- b)42o
- c)52o
- d)48o
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB ...
In ∆ BDC and ∆ BAC
Angle BAC = BDC
(angle made on same segment BC)
Since ABC is making right angle (90)
So,
In ∆ABC
ABC +BAC+ACB=180
(angle sum property of triangle)
90+42+ACB=180
ACB=180-132
ACB=48o
Angle BAC = BDC
(angle made on same segment BC)
Since ABC is making right angle (90)
So,
In ∆ABC
ABC +BAC+ACB=180
(angle sum property of triangle)
90+42+ACB=180
ACB=180-132
ACB=48o
Most Upvoted Answer
In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB ...
In ∆ BDC and ∆ BAC
Angle BAC = BDC
(angle made on same segment BC)
Since ABC is making right angle (90)
So,
In ∆ABC
ABC +BAC+ACB=180
(angle sum property of triangle)
90+42+ACB=180
ACB=180-132
ACB=48o
Angle BAC = BDC
(angle made on same segment BC)
Since ABC is making right angle (90)
So,
In ∆ABC
ABC +BAC+ACB=180
(angle sum property of triangle)
90+42+ACB=180
ACB=180-132
ACB=48o
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Community Answer
In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB ...
In ∆ BDC and ∆ BAC
Angle BAC =BDC
(angle made on same segment BC)
Since ABC is making right angle (90)
So,
In ∆ABC
ABC +BAC+ACB=180
(angle sum property of triangle)
90+42+ACB=180
ACB=180-132
ACB=48
Angle BAC =BDC
(angle made on same segment BC)
Since ABC is making right angle (90)
So,
In ∆ABC
ABC +BAC+ACB=180
(angle sum property of triangle)
90+42+ACB=180
ACB=180-132
ACB=48
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In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB is equal toa)58ob)42oc)52od)48oCorrect answer is option 'D'. Can you explain this answer? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB is equal toa)58ob)42oc)52od)48oCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB is equal toa)58ob)42oc)52od)48oCorrect answer is option 'D'. Can you explain this answer?.
In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB is equal toa)58ob)42oc)52od)48oCorrect answer is option 'D'. Can you explain this answer? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB is equal toa)58ob)42oc)52od)48oCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the given circle, O is the centre and∠BDC = 42o. Then,∠ACB is equal toa)58ob)42oc)52od)48oCorrect answer is option 'D'. Can you explain this answer?.
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