CA Foundation Exam > CA Foundation Questions > If p, q and r are in A.P. and x, y, z are in ...
Start Learning for Free
If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal to
- a)0
- b)– 1
- c)1
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r...
Free Test
FREE
| Start Free Test |
Community Answer
If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r...
Solution:
Given, p, q, and r are in A.P. and x, y, and z are in G.P.
We know that for a G.P., the product of the first and third terms is equal to the square of the second term, i.e., xy = z².
Similarly, for an A.P., the sum of the first and third terms is twice the second term, i.e., p + r = 2q.
Using these relations, we can simplify the expression xqr. y rp. zpq as follows:
xqr. y rp. zpq = xyz. qrp. p²z
= xyz. q(p + r). pz
= xyz. q(2q). pz (using p + r = 2q)
= 2q³xyzp
= 2(xyzp)³/3
= 2z³p³ (since xy = z²)
= 2(pz)³/3
= 2(pq/2)³/3 (since p + r = 2q)
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
Given, p, q, and r are in A.P. and x, y, and z are in G.P.
We know that for a G.P., the product of the first and third terms is equal to the square of the second term, i.e., xy = z².
Similarly, for an A.P., the sum of the first and third terms is twice the second term, i.e., p + r = 2q.
Using these relations, we can simplify the expression xqr. y rp. zpq as follows:
xqr. y rp. zpq = xyz. qrp. p²z
= xyz. q(p + r). pz
= xyz. q(2q). pz (using p + r = 2q)
= 2q³xyzp
= 2(xyzp)³/3
= 2z³p³ (since xy = z²)
= 2(pz)³/3
= 2(pq/2)³/3 (since p + r = 2q)
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
= (pq/2)²
= (q² - (p/2)²)
= (r² - (q/2)²) (since p, q, and r are in A.P.)
= (rp/2)²
Attention CA Foundation Students!
To make sure you are not studying endlessly, EduRev has designed CA Foundation study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CA Foundation.
|
Explore Courses for CA Foundation exam
|
|
Similar CA Foundation Doubts
Top Courses for CA FoundationView all
If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer?
Question Description
If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer?.
If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for CA Foundation.
Download more important topics, notes, lectures and mock test series for CA Foundation Exam by signing up for free.
Here you can find the meaning of If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If p, q and r are in A.P. and x, y, z are in G.P. then xq–r. y r–p. zp–q is equal toa)0b)– 1c)1d)none of theseCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice CA Foundation tests.
|
|
Explore Courses for CA Foundation exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup